Altering Strings in Python Functions

Question

So i have a basic problem; I have the user call a function which takes a string input for example, lets say in this case apples. so the function, get_view, is called get_view('apples') and its job is to convert all characters in apples to hidden characters, example for 'apples'-->'^^^^^^', hello world would become '^^^^^ ^^^^^', and etc, my problem is that in my code below it does convert all letters and numbers and etc but it does not leave the empty space present between hello world, and it also does not consider ('). How can i modify my code to make it fully functional?

code :

def get_view(puzzle):

    view = puzzle
    length = len(puzzle)
    for index in range(0,length):
        if ((puzzle[index]) != '' or '-' ):
            view = view[: index] + HIDDEN + view[index+1:]

HIDDEN = '^' (its a constant)

Thank you, new to the website <3

please specify what character should be converted - because a space is a character after all.. — Aprillion
– Aprillion, Commented Oct 19, 2012 at 0:24
@user1757870: Please don't destroy your own questions -- it significantly lowers the value of the answers that people spent time working to craft. — DSM
– DSM, Commented Oct 19, 2012 at 2:09

Aprillion · Accepted Answer · 2012-10-19 00:37:03Z

2

i use regex functions like re.sub() for most non-trivial string operations, like this:

import re
print(re.sub("[a-zA-Z0-9_']", "^", "Hello world, what's up?"))
#                                   ^^^^^ ^^^^^, ^^^^^^ ^^?

edited Oct 19, 2012 at 0:37

answered Oct 19, 2012 at 0:28

Aprillion

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3 Comments

Jason Sperske Over a year ago

Add , flags=re.IGNORECASE or update your regex to get uppercase letter.

Jason Sperske Over a year ago

"\S" would do anything that isn't a space

Aprillion Over a year ago

@JasonSperske thanks for the comments, the question isn't clear about what characters should and should not be "hidden"

Elias Zamaria · Accepted Answer · 2012-10-19 00:08:27Z

1

Are you trying to do something like this?

view = ''.join((HIDDEN if c.isalnum() else c) for c in puzzle)

answered Oct 19, 2012 at 0:08

Elias Zamaria

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Comments

mhawke · Accepted Answer · 2012-10-19 00:51:45Z

1

Assuming then that you do not want to alter white space characters (space, tab, new-line), this is one way to do it using a for loop:

def get_view(puzzle, hide_char='^'):
    view = []
    for c in puzzle:
        if not c.isspace():
            view.append(hide_char)
        else:
            view.append(c)
    return ''.join(view)

Alternatively (and better) is to use a list comprehension:

def get_view(puzzle, hide_char='^'):
    view = [c if c.isspace() else hide_char for c in puzzle]
    return ''.join(view)

or just:

def get_view(puzzle, hide_char='^'):
    return ''.join(c if c.isspace() else hide_char for c in puzzle)

answered Oct 19, 2012 at 0:51

mhawke

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