Remove numbers from array of strings

Question

I have an array that looks like this:

["lorem", "ipsum", "1734", "dolor", "1", "301", "et", "4102", "92"]

Is there a way to remove all the numbers in the array, even though they're stored as strings, so that I'd be left with this:

["lorem", "ipsum", "dolor", "et"]

Thanks for any hints.

Is there ever a possibility of having float strings "0.12" or even scientific notation "3.4e-10"? Can some strings have multiple lines in them? — Phrogz
– Phrogz, Commented Oct 18, 2012 at 17:14

Simone Carletti · Accepted Answer · 2012-10-18 17:16:14Z

5

Use a regexp pattern

s = ["lorem", "ipsum", "1734", "dolor", "1", "301", "et", "4102", "92"]
s.reject { |l| l =~ /\A\d+\z/ }
# => ["lorem", "ipsum", "dolor", "et"]

edited Oct 18, 2012 at 17:16

answered Oct 18, 2012 at 17:10

Simone Carletti

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3 Comments

mu is too short Over a year ago

There's also reject { |w| w !~ /\D/ } if you don't mind triple negatives (reject, doesn't match, not digit).

Simone Carletti Over a year ago

@muistooshort In that case you can use select instead of reject. ;)

mu is too short Over a year ago

But then you're stuck with the anchors again and you don't get to make everyone question the difference between genius and insanity :)

ChuckE · Accepted Answer · 2012-10-18 17:11:35Z

4

s = ["lorem", "ipsum", "1734", "dolor", "1", "301", "et", "4102", "92"]
s.reject{|s| s.match(/^\d+$/) }

answered Oct 18, 2012 at 17:11

ChuckE

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Comments

Phrogz · Accepted Answer · 2012-10-18 17:20:51Z

3

If all your strings are just integers, @Simone's answer will work nicely.

If you need to check for all numeric representations (floats and scientific notation) then you can:

s = %w[ foo 134 0.2 3e-3 bar ]
s.reject!{ |str| Float(str) rescue false }
p s
#=> ["foo", "bar"]

answered Oct 18, 2012 at 17:20

Phrogz

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Comments

Tim · Accepted Answer · 2017-05-09 07:27:30Z

0

One way I can say is: REGEX match

Loop though all the items

Then use this:

txt='Your string'

re1='(\\d+)'    # Integer Number 1

re=(re1)
m=Regexp.new(re,Regexp::IGNORECASE);
if m.match(txt)
    int1=m.match(txt)[1];
    # REMOVE THE ITEM HERE
end

edited May 9, 2017 at 7:27

Tim

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answered Oct 18, 2012 at 17:12

Pradip

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