Get file name of file used to open the associated application

Question

I want to write a small app that does some data manipulation on the contents of a simple text file.

I just want to be able to right click such a file, choose 'Open with' in Windows, select my app, then the app opens, parses the file, does some stuff and closes immediately again.

Question: when my app starts, how do I get the file name that triggered the app to start?

Thanks!

Oh great! I knew it must have been somthing simple like that, but when I tried Googling it, I really couldn't find this... Thanks! — SonOfGrey
– SonOfGrey, Commented Oct 3, 2012 at 15:04
@kobik - Interesting. I wonder why who deleted your comment did not delete mine.. — Sertac Akyuz
– Sertac Akyuz, Commented Oct 3, 2012 at 17:22

TridenT · Accepted Answer · 2012-10-03 15:06:27Z

6

You get the file as parameter number 1.
You can get it with the function ParamStr(1).

Have a look here for more details:
http://www.delphibasics.co.uk/RTL.asp?Name=ParamStr

For your information, ParamStr(0) is the filename (including complete path) of your EXE application.

answered Oct 3, 2012 at 15:06

TridenT

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4 Comments

David Heffernan Over a year ago

I'm curious. Why link to delphibasics rather than the actual documentation? docwiki.embarcadero.com/Libraries/en/System.ParamStr

Andreas Rejbrand Over a year ago

And ParamStr(0) is the same thing as Application.ExeName, btw.

TridenT Over a year ago

@DavidHeffernan Very bad experience with Delphi documentation (you know, since Delphi7 blablabla ...) so I'm still using so (old) bookmark :)

Tom Over a year ago

@DavidHeffernan Because DelphiBasics is awesome and Embarcadero documentation is total crap. They should just take the good, old Delphi7 documentation and publish on the website.

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