Java array get value at index method

Question

I making a dynamic array that using normal array and mimic arraylist. So.... Please help me check if the method is correct. rangeCheck is a boolean method checking if the array is out of bound. rangeCheck contains an outofbound exception.

 public int get(int position)
{
    rangeCheck(position);
    int valuePosition =0;
    for(int count=0;count == position;count++)
    {
        valuePosition = storage[count] ;
    }
    return valuePosition; 
}

For some idiotic reason, I keep thinking inorder to get to some value at some specific index, I have to go in a loop to do it....

Your loop doesn't make any sense. What are you trying to accomplish with it? — Ted Hopp
– Ted Hopp, Commented Oct 3, 2012 at 1:00
Why dont you use ArrayList? ArrayList's get is O(1) and contains is O(n), thats really the best your solution can hope for so why not just use it? — cobolstinks
– cobolstinks, Commented Oct 3, 2012 at 1:15
dude... as I said, I using normal array and mimic array list with a growth method... — Ryoko Nela
– Ryoko Nela, Commented Oct 3, 2012 at 1:41

juergen d · Accepted Answer · 2012-10-03 00:59:59Z

3

how about

public int get(int position)
{
    boolean ok = rangeCheck(position);
    if(! ok)        
        throw new IndexOutOfBoundsException("Your error message");
    return storage[position];
}

answered Oct 3, 2012 at 0:59

juergen d

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2 Comments

Zéychin Over a year ago

Barely beat me to it, but I would add rangeCheck(position) before the first line of the body.

arshajii Over a year ago

Maybe throw an exception instead of return some_errorcode? But yes, the idea is the same (+1).

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