javascript to php value not sending/adding

Question

I must be tired or something because i am unable to get this line of code to work:

var all = color.val('all');
$('#cssColor" + <?php echo $page ?> + "', parent.document).attr("background-color", all.hex);

I even have a textbox with the page value as well and i try:

var all = color.val('all');
$('#cssColor" + $('#txtPageValue').val() + "', parent.document).attr("background-color", all.hex);

I can not seem to send the page value!

What are you trying to do with var all = color.val('all'); ?? — Hazem Salama
– Hazem Salama, Commented Sep 30, 2012 at 4:49
@hsalama: Its a hex color value. It comes formatted like #54ff65 etc etc — StealthRT
– StealthRT, Commented Sep 30, 2012 at 4:50
I'm pretty sure this code snippet is riddled with parse errors... — Richard JP Le Guen
– Richard JP Le Guen, Commented Sep 30, 2012 at 4:52
... for example $('#cssColor" +... why do you open with single quotes and finish with double quotes? — Richard JP Le Guen
– Richard JP Le Guen, Commented Sep 30, 2012 at 4:52

Mahdi · Accepted Answer · 2012-09-30 08:44:52Z

1

Try to change this one:

$('#cssColor" + <?php echo $page ?> + "',

to:

$('#cssColor<?php echo $page ?>',

And also, for the second one:

$('#cssColor" + $('#txtPageValue').val() + "',

to:

$('#cssColor' + $('#txtPageValue').val(),

answered Sep 30, 2012 at 8:44

Mahdi

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Bryan Gentry · Accepted Answer · 2012-09-30 05:03:39Z

1

I am not sure how you are assigning the all variable, but assuming it is getting assigned correctly, you could rewrite your code something like this to get the value to appear in the right place in your javascript:

<?php echo "<script type='text/javascript'>
        //code somewhere in here should define the color object
        var all = color.val('all')
        $('#cssColor" . $page . "', parent.document).attr('background-color', all.hex);
    </script>"; ?>

This writes the javascript to the document, without breaking the echo function in the middle.

Or, you could do this:

var all = color.val('all');
$('#cssColor'+<?php echo $page; ?>, parent.document).attr('background-color', all.hex);

answered Sep 30, 2012 at 5:03

Bryan Gentry

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