How to sort objects in java? [duplicate]

Question

Possible Duplicate:
How to sort an arraylist of objects by a property?
What is the sorting algorithm for Java

I have a class in java that keeps record of diffSeconds.

class fileObj
    {
        public String fileName; 
        public Date modificationTime; 
        public long diffSeconds;     

        fileObj()
        {
            modificationTime = null; 
        }
    }

I have a forloop that makes multiple instances of the fileObj class and adds them to a list.

List<fileObj> fileView = new ArrayList<fileObj>();
for(int j=0; j<10; j++)
       {
         fileView.add(new fileObj());
       }

Assuming that each class has a diffSeconds values assigned to them, how can i order the list depending on the value (largest first)

possible duplicate of How to sort an arraylist of objects by a property? and How to sort an array of objects in Java — DNA
– DNA, Commented Sep 22, 2012 at 19:39

swemon · Accepted Answer · 2012-09-22 09:11:20Z

You can use Collections.sort(fileView); and implement Comparable interface and write implemented method compareTo(fileObj arg0) which decide for sorting your list.

For implementation,

class fileObj implements Comparable<fileObj>

@Override
    public int compareTo(fileObj arg0) {

        if(this.diffSeconds > arg0.diffSeconds )
        return 0;
        else return 1;
    }

Reference:

Detail Coding.

import java.util.ArrayList;
import java.util.Collections;
import java.util.Date;
import java.util.List;


public class SortExample {

    /**
     * @param args
     */
    public static void main(String[] args) {
        // TODO Auto-generated method stub

        List<fileObj> fileView = new ArrayList<fileObj>();
        for(int j=0; j<10; j++)
               {
                 fileView.add(new fileObj(j));
               }
        Collections.sort(fileView);

        for(fileObj obj: fileView){
            System.out.println("File " + obj.getDiffSeconds());
        }


    }

}
class fileObj implements Comparable<fileObj>
{
    public String fileName; 
    public Date modificationTime; 
    public long diffSeconds;     

    fileObj()
    {
        modificationTime = null; 
    }

    fileObj(long diffSeconds)
    {
        modificationTime = null;
        this.diffSeconds = diffSeconds;
    }

    @Override
    public int compareTo(fileObj arg0) {

        if(this.diffSeconds > arg0.diffSeconds )
        return 0;
        else return 1;
    }

    public long getDiffSeconds() {
        return diffSeconds;
    }

    public void setDiffSeconds(long diffSeconds) {
        this.diffSeconds = diffSeconds;
    }
}

PermGenError · Accepted Answer · 2012-09-22 09:00:15Z

0

use comparator or comparable interfaces.

answered Sep 22, 2012 at 9:00

PermGenError

46.5k8 gold badges90 silver badges107 bronze badges

Comments

dareurdream · Accepted Answer · 2012-09-22 09:07:03Z

0

Look at the link below :-

http://docs.oracle.com/javase/6/docs/api/java/util/Arrays.html

Search for the sort method which takes objects as parameter and implement comparable interface in your class.

answered Sep 22, 2012 at 9:07

dareurdream

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