single byte array to 2d byte array in C#?

Question

I have a byte array of

byte[] d = new byte[64];

now i want to convert it to a 2d byte array like ..

byte[,] data = new byte[8,8];

can any one help me on this

Adil · Accepted Answer · 2012-09-22 06:29:12Z

6

This could be one of method.

byte[] d = new byte[64];
byte[,] data = new byte[8,8];

int row = 0;
int column = 0;

for(i=0; i < d.Length; i++)
{
   row = i%8;
   column = i/8;
   data [row, column] = d[i];    
}

edited Sep 22, 2012 at 6:29

answered Sep 22, 2012 at 6:15

Adil

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4 Comments

Drone Over a year ago

yeah thanks but need some editing if u permit me i will do it in the ans .. it worked for me thanks

Adil Over a year ago

You can or You can tell me so that I would make that.

Drone Over a year ago

make it d.Length and data[column,row] thats it

Adil Over a year ago

Thanks @Drone, So nice of you. Made those changes.

dtb · Accepted Answer · 2012-09-22 06:20:00Z

4

You can use the Buffer.BlockCopy Method:

byte[] d = new byte[64];
byte[,] data = new byte[8,8];

Buffer.BlockCopy(d, 0, data, 0, 64);

answered Sep 22, 2012 at 6:20

dtb

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Comments

Adriaan Stander · Accepted Answer · 2012-09-22 06:27:09Z

0

How about something like

byte[] d = new byte[64];

for (byte i = 0; i < d.Length; i++)
    d[i] = i;

byte[,] data = new byte[8, 8];

Enumerable.Range(0, 8).ToList().
    ForEach(i => Enumerable.Range(0, 8).ToList().
        ForEach(j => data[i, j] = d[i * 8 + j]));

answered Sep 22, 2012 at 6:27

Adriaan Stander

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