Javascript - Check if a certain index has a certain value in an array

Question

I have an array with 144 indexes, that I fill with data from a form. I want to check if a certain index contains a certain value, and I don't know if such function exists in JavaScript, or how to make said function.
Can you help me make a function that gets an array, a certain index and a certain value as parameters and return true if it exists?

An example:

var board = new Array();
board.push('X');
board.push('O');
function inArrayatindex(array, index, value)
{
/* if(certain code that i need help with...)
{
return true;
}
}
inArrayatindex(board, 2, 'O'); //returns true
inArrayatindex(board, 2, 'o'); // returns false
inArrayatindex(board, 3, 'X'); // returns false

I'm sorry if i misunderstood your question, but shouldn't just be array[index] === value? — xdazz
– xdazz, Commented Sep 16, 2012 at 6:44

Gregor · Accepted Answer · 2012-09-16 06:41:46Z

4

try this:

function check(array, index, value) {
    if(index < 0 || index >= array.length) {
         return false;
    }
    return array[index] === value;
}

answered Sep 16, 2012 at 6:41

Gregor

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Comments

AboQutiesh · Accepted Answer · 2012-09-16 06:47:09Z

0

I think that is what you need,

function inArray(array,valueToMatch){

  var myArray = array
  var index = -1;

  for(int i=0;i<myArray.length;i++){
      if(myArray[i].match(valueToMatch)){
        index = i;
      }   
   }

  return index;
}

note : array parameter your 144 index array

valueToMatch parameter is the value you search for

answered Sep 16, 2012 at 6:47

AboQutiesh

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Comments

Lars Flieger · Accepted Answer · 2022-03-30 13:54:01Z

0

Update 2022

With ES2022 you can use Array.prototype.at():

function isValueAtIndex(array, index, value) {
    return array.at(index) === value
}

You can check from the end with negative index.
You do not have to check length since at will return undefinded if the given index can not be found.

answered Mar 30, 2022 at 13:54

Lars Flieger

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