How to use php 'exec' to run .jar with input parameters

Question

I have a php file which runs a '.jar' file. Code is given bellow

exec("java -Xmx1g -jar \"C:\Users\Roxy\Documents\NetBeansProjects\Entity Extraction\dist\Entity Extraction.jar",$output);

This works fine without any error
But now I need to pass an array (lets say $testArray) with this command to 'Entity Extraction.jar' file and access it in my main method in java code.

Can anyone please tell me how to do this?

Update:

In my php file, I have

$testArr[0] = 'test1';
$testArr[1] = 'test2'; 

$str = "java -Xmx1g -jar \"C:\Users\Roxy\Documents\NetBeansProjects\Entity Extraction\dist\Entity Extraction.jar ";

foreach($testArr as $param){
 $str.=$param.' ';
}

exec($str,$output);
print_r($output);

In my java Main Class, I have

public static void main(String[] args) {
     int length = args.length;
     for (int i = 0; i < length; i++) {
          System.out.println(args[i]);
     }
}

You should be able to just add the array to the exec command, provided it is composed of strings, and can then access it in your java main via the args parameter (it will show up as a single String which you'll have to split). However, could you elaborate where you're going with this? This kinda sounds like a bad thing to do in the first place... — sarcan
– sarcan, Commented Aug 12, 2012 at 12:40
can you please tell me how to use it in 'exec' code and use it in main method(if you can with an example). — Roshanck
– Roshanck, Commented Aug 12, 2012 at 12:43

Tomer · Accepted Answer · 2012-08-12 12:48:38Z

1

When running a jar in the command line, every parameter you put after Extraction.jar separated by a space will automatically go into the args array.

So you need to run on the array and build the string you want to pass:

 $str = "java -Xmx1g -jar \"C:\Users\Roxy\Documents\NetBeansProjects\Entity Extraction\dist\Entity Extraction.jar ";

foreach($testArr as $param){
 $str.=$param.' ';
}

exec($str,$output);

This is assuming the array only contains strings or numbers. if it contains objects or other arrays, you need to manipulate this code a bit, but you get the idea.

answered Aug 12, 2012 at 12:48

Tomer

17.9k16 gold badges82 silver badges139 bronze badges

Sign up to request clarification or add additional context in comments.

14 Comments

Roshanck Over a year ago

This doesn't work. I add $testArr[0] = 'test1';$testArr[1] = 'test2'; before '$str=....' argument. Add bellow command in my main method. int length = args.length; for (int i = 0; i < length; i++) { System.out.println(args[i]); }

Tomer Over a year ago

Please update the question with the code you tried, its hard to see it in the comments.

Roshanck Over a year ago

I tried this with the command prompt also just by giving single string after the 'Extraction.jar '. But it says 'unable to access jarfile ...'

Roshanck Over a year ago

It works in the command prompt when I went into the 'dist' folder using cd command and then run the .jar file with a input parameter?

Tomer Over a year ago

is your jar name "entity extraction.jar" with a space? if so that is a big no-no, change it to entity_extraction.jar and try again

|

JohnHoulderUK · Accepted Answer · 2012-08-12 12:39:44Z

0

you could pass print_r($testArray,true); or you could write a function that cycles through the array and creates a list.

answered Aug 12, 2012 at 12:39

JohnHoulderUK

6792 gold badges8 silver badges27 bronze badges

2 Comments

Roshanck Over a year ago

how do I pass 'print_r($testArray,true);' with 'exec' ?

JohnHoulderUK Over a year ago

you can either do exec("stuff here ".print_r($testArray,true)." other stuff here"); or pass it via a variable using $params = print_r($testArray,true);

Collectives™ on Stack Overflow

How to use php 'exec' to run .jar with input parameters

2 Answers 2

14 Comments

2 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

14 Comments

2 Comments

Your Answer

Sign up or log in

Post as a guest

Related