Convert XML String to ArrayList

Question

Seems like a basic question but I can't find this anywhere. Basically I've got a list of XML links like so: (all in one string)

I already have the "string" var which contains all the XML. Just extracting the HTML strings.

<?xml version="1.0" encoding="UTF-8"?>
<fql_query_response xmlns="http://api.facebook.com/1.0/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" list="true">
<photo>
    <src_small>http://photos-a.ak.fbcdn.net/hphotos-ak-ash4/486603_10151153207000351_1200565882_t.jpg</src_small>
</photo>
<photo>
  <src_small>http://photos-c.ak.fbcdn.net/hphotos-ak-ash3/578919_10150988289678715_1110488833_t.jpg</src_small>
</photo>

I want to convert these into a arrayList, so something like URLArray[0] would be the first address as a string.

Can anyone tell me how to do this thanks?

use an XMLReader to parse the XML, building out your ArrayList during parsing. — CSmith
– CSmith, Commented Aug 6, 2012 at 17:32
This question stackoverflow.com/questions/3625506/… has some good XML parser choices for android. — Vikdor
– Vikdor, Commented Aug 6, 2012 at 17:34
Way to much code for something that should be a simple task? — Oliver Dixon
– Oliver Dixon, Commented Aug 6, 2012 at 17:56
This is one of the best answers for this question stackoverflow.com/a/4828765/1087653 — FredFloete
– FredFloete, Commented Aug 6, 2012 at 17:57

srini.venigalla · Accepted Answer · 2012-08-06 20:43:22Z

7

  DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
  DocumentBuilder builder = factory.newDocumentBuilder();
  InputSource is = new InputSource( new StringReader( xmlString) );
  Document doc = builder.parse( is );

  XPathFactory factory = XPathFactory.newInstance();
  XPath xpath = factory.newXPath();
  xpath.setNamespaceContext(new PersonalNamespaceContext());
  XPathExpression expr = xpath.compile("//src_small/text()");

  Object result = expr.evaluate(doc, XPathConstants.NODESET);
  NodeList nodes = (NodeList) result;
  List<String> urls = new ArrayList<String>();
  for (int i = 0; i < nodes.getLength(); i++) {
      urls.add (nodes.item(i).getNodeValue());
      System.out.println(nodes.item(i).getNodeValue()); 
  }

edited Aug 6, 2012 at 20:43

answered Aug 6, 2012 at 17:42

srini.venigalla

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3 Comments

Oliver Dixon Over a year ago

What's the personal namespace? I'm getting the error PersonalNamespaceContext cannot be resolved to a type

srini.venigalla Over a year ago

that's the xmlns attribute, remove it and try?

Oliver Dixon Over a year ago

Ah it wasn't in my library, I downloaded here: code.google.com/p/fabulous/source/browse/branches/3.0/3.0.0/src/… Works great, thanks so much you've saved me hours.

Colin D · Accepted Answer · 2012-08-06 17:44:36Z

3

You are right, there should be some other resources out there that can help you. Maybe your searches just do not use the right keywords.

You basically have 2 choices:

Use an XML processing library. SAX, DOM, XPATH, & xmlreader are some keywords you can use to find some.
Just ignore the fact that your string is xml and perform normal string operations on it. splits, iterate through it, regular expressions, ect...

edited Aug 6, 2012 at 17:44

answered Aug 6, 2012 at 17:32

Colin D

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Comments

MAC · Accepted Answer · 2012-08-06 17:34:13Z

-2

Yes for that you have to perform XML Parsing.

then store that in ArrayList.

ex:

ArrayList<String> aList = new ArrayList<String>();

aList.add("your string");

answered Aug 6, 2012 at 17:34

MAC

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