Javascript replace with regular expression - Replace only part of string found

Question

I have a string that looks like the following:

"01/11/2012 (Last, First) - Notes,02/11/2012 (Last, First) - More Notes,03/11/2012 (Last, First) - Even More Notes,09/12/2012 (Last, First) - You get the idea"

I would like each note to fall on a new line by replacing any comma followed by a number with '\n'.

I have tried .replace(/,/g, '\n') but I get a newline in the middle of the name.
So I do .replace(/,\d/g, '\n'), however then I loose the first number of the date.

How can I search for ,# and replace it with \n# where the number is the same as it was previously?

I want the result to look like this:

01/11/2012 (Last, First) - Notes
02/11/2012 (Last, First) - More Notes
03/11/2012 (Last, First) - Even More Notes
09/12/2012 (Last, First) - You get the idea

Claudio Acciaresi · Accepted Answer · 2012-08-06 14:22:44Z

2

You can use a capture to avoid missing that number:

s.replace(/,(\d)/g, '\n$1')

edited Aug 6, 2012 at 14:22

user1106925

answered Aug 6, 2012 at 14:18

Claudio Acciaresi

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2 Comments

Jeremy A. West Over a year ago

Thanks, I had done this in the past, I just was having trouble finding the syntax anywhere. Monday morning Google skill need some work :)

Claudio Acciaresi Over a year ago

No problem :). All Monday mornings always need some tuning of ourselves.

freefaller · Accepted Answer · 2012-08-06 14:18:15Z

2

(Update, sorry, just noticed that you don't want the comma)

Try...

.replace(/,(\d)/g, '\n$1')

This groups the \d and then uses it (with $1) in the replace

answered Aug 6, 2012 at 14:18

freefaller

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