using the awk variable in bash

Question

I have an awk script that takes the number of total eth interrupts in the system.

#!/bin/bash

FILE="/proc/interrupts"

awk 'NR==1 {
core_count = NF 
print "core count: ", core_count
next
}

/eth/ {
 for (i = 2; i <= 2+core_count; i++)
 totals[i-2] += $i
}

END {
print "Totals"
for (i = 0; i < core_count; i++)
printf("CPU%d: %d\n", i, totals[i])
}
' $FILE

At the end of this in bash, I have the core_count and the totals array. but then, I need to use these variables, how can I use them at the rest of the script?In other words how can you globalize them?

Ignacio Vazquez-Abrams · Accepted Answer · 2012-07-23 05:43:17Z

2

You can't. Echo them out and pull them in.

{ read core_count ; read -a totals ; } < <(echo -e "2\n4 5")

answered Jul 23, 2012 at 5:43

Ignacio Vazquez-Abrams

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Comments

perreal · Accepted Answer · 2012-07-23 06:00:31Z

1

#!/bin/bash

FILE="/proc/interrupts"

output=$(awk 'NR==1 {
core_count = NF 
print core_count
next
}

/eth/ {
 for (i = 2; i <= 2+core_count; i++)
 totals[i-2] += $i 
}

END {
for (i = 0; i < core_count; i++)
  printf("%d\n", totals[i])
}
' $FILE)
core_count=$(echo $output | cut -d' ' -f1)
output=$(echo $output | sed 's/^[0-9]*//')
totals=(${output// / })
echo CC: $core_count total0 ${totals[0]} total1 ${totals[1]}

answered Jul 23, 2012 at 6:00

perreal

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1 Comment

tripleee Over a year ago

To avoid the duplicate echo | ... code, set $output will tokenize the output and replace $1, $2 etc with the tokenized values. Also note that echo is problematic, and should be avoided. At a minimum, you should quote the strings you echo, generally.

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