JSON returned from php is [obejct Object] and jQuery.parseJSON is null

Question

In my php file I have:

$arr[] = array("status"=>0);
echo json_encode($arr);

In my javascript, I have:

$(document).ready(function(){

    initialize(); 
    $("#searchbutton").click(function(){

    var usrinput = $("#userinput").val();

    $.get(
        "searchpageajaxjson.php",
        {searchterm: usrinput},
        function(data){
            searchreturned(data);
        },
        "json"
    ); 
    });
 });


function searchreturned(data){
   console.log(data); 
   var parsed = jQuery.parseJSON(data);
   console.log(parsed); 
   //for (var i = 0; i < parsed.length; i++) {  
    //            alert(parsed[i]);  
    //     } 
   //    
}

The console.log(data) shows [object Obejct] and console.log(parsed) shows null

Where am I going wrong?

Edited to Add:

alert(data.status) shows undefined.

Second Edit:

I'm really grateful for all the help I've received. It's hard to pick an answer, because I'm really only able to move on from this problem due to all the help received in all the comments. I am always in awe of you kind folks who give your time to helping newbies like myself.

Can you please share the json as text and the [Object object]? — Oscar Jara
– Oscar Jara, Commented Jul 22, 2012 at 23:39
What console are you using? It should show the object properties. — Esailija
– Esailija, Commented Jul 22, 2012 at 23:39
You jumped from using $. as the jQuery identifier and then to jQuery. - any reason? $.parseJSON would have worked too... — Lix
– Lix, Commented Jul 22, 2012 at 23:42
@Esailija. This is the first time I am doing this - I opened up the developer tools on the browser (IE) and there is a console tab which shows the following: LOG: [object Object] LOG: null — Valerie Parker
– Valerie Parker, Commented Jul 22, 2012 at 23:42

Ry- · Accepted Answer · 2012-07-22 23:44:02Z

2

You're not supposed to call jQuery.parseJSON on data again. jQuery takes care of that for you already, since you used "json" as the dataType.

answered Jul 22, 2012 at 23:44

Ry-♦

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7 Comments

Valerie Parker Over a year ago

Would it make a difference if I said even before attemping to use parse.JSON, alert(data.status) is saying undefined?

Ry- Over a year ago

@ValerieParker: Yes, it would. Make sure the PHP outputs no warnings or other cruft apart from the JSON.

Valerie Parker Over a year ago

That echo json_encode($arr) statement is the only echo statement. I do have this sort of thing as well: if (!$connection){ die('Not connected: '.mysql_error()); }

Ry- Over a year ago

@ValerieParker: Yes, it would, if there was an error. Or, if you have warnings and such turned on, other problems could be causing it too. Which browser are you using?

Ry- Over a year ago

@ValerieParker: Also, alert(data.status) isn't the right one. Try alert(data[0].status) instead.

|

Oscar Jara · Accepted Answer · 2012-07-22 23:56:48Z

1

1. There is no reason to call jQuery.parseJSON or $.parseJSON because jQuery knows that is already a JSON object due to the "json" parameter you passed here:

$.get('source', {param:param}, function(data){ /*work with data*/ }, "json");

2. If console.log(data); is not null and you are getting some [Object Object] try to see what are the properties of that object, like this:

e.g: Explore your object:

enter image description here

e.g: Print value from object:

//this will output "Horror"
data.genre

Hope this helps you.

edited Jul 22, 2012 at 23:56

answered Jul 22, 2012 at 23:51

Oscar Jara

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1 Comment

Valerie Parker Over a year ago

Oscar Jara, thanks, I now understand what you mean. And when I used the Chrome console instead, I can see the values.

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