Error for python code

Question

The following code return an error KeyError: 500

def my_func(self, limit, list_type, **args):
    type2abbr = {"allcategories": "ac", "categorymembers":"cm"}
    abbr = type2abbr[list_type]
    yield abbr
if __name__ == "__main__":
    abbr = my_func(500, "categorymembers")
    print abbr

Output:

    Traceback (most recent call last):
      File "dater.py", line 72, in 
        bot.start()
      File "dater.py", line 56, in start
        for title, text in self.pages:
      File "dater.py", line 25, in page_generator
        for item in self.cats:
      File "/home/ceradon/api.py", line 305, in list
        abbr = type2abbr[list_type]
    KeyError: 500

Can anyone help me figure this out please?

If you run that code it will do nothing, because you never call the function in the code you posted. You need to provide more info about how you are calling it (e.g., what arguments you pass). — BrenBarn
– BrenBarn, Commented Jul 22, 2012 at 3:10
Without more code, it would be hard to fully diagnose. It looks like list_type is 500. You'd have to help us understand why. — Ned Batchelder
– Ned Batchelder, Commented Jul 22, 2012 at 3:10
Also, it seems strange to have a function with no loop using a yield statement. Are you sure you want yield and not simply return? — Greg Hewgill
– Greg Hewgill, Commented Jul 22, 2012 at 3:14
Since it doesn't look like you're using it inside of an object, is there any reason to include self? — Makoto
– Makoto, Commented Jul 22, 2012 at 3:20

Kevin Grant · Accepted Answer · 2012-07-22 03:26:22Z

5

You've implemented my_func as if it were a method (i.e. assuming self) but you are not calling it on any object.

Either you should have an object, e.g. x.my_func(...), or you should remove self, from the argument list.

answered Jul 22, 2012 at 3:26

Kevin Grant

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