PHP. How to repeat and modify HTML code for array elements?

Question

I have $array=array("nothing","1","2","3","4","5","6","7","8","9","10"); and a piece of code as a template:

$var=<<<EOF

$array[0]
<div>
  <!-- something else -->
  <ul>
    <li>$array[1]</li>
    <li>$array[2]</li>
    <li>$array[3]</li>
  </ul>
  <!-- something else -->
</div>

EOF;

I want dynamically repeat and modify this HTML code while there are array elements. I mean this result:

$var=<<<EOF

$array[0]
<div>
  <!-- something else -->
  <ul>
    <li>$array[1]</li>
    <li>$array[2]</li>
    <li>$array[3]</li>
  </ul>
  <!-- something else -->
</div>
<div>
  <!-- something else -->
  <ul>
    <li>$array[4]</li>
    <li>$array[5]</li>
    <li>$array[6]</li>
  </ul>
  <!-- something else -->
</div>
<div>
  <!-- something else -->
  <ul>
    <li>$array[7]</li>
    <li>$array[8]</li>
    <li>$array[9]</li>
  </ul>
  <!-- something else -->
</div>
<div>
  <!-- something else -->
  <ul>
    <li>$array[10]</li>
  </ul>
  <!-- something else -->
</div>

EOF;

Check out the manual entry on foreach loops.

Madara's Ghost
– Madara's Ghost

2012-07-20 13:41:44 +00:00
Commented Jul 20, 2012 at 13:41 — Madara's Ghost
– Madara's Ghost, Commented Jul 20, 2012 at 13:41

Community · Accepted Answer · 2020-06-20 09:12:55Z

2

Expanding on @Nadav's answer and making it better:

<?php
$array = array(0);

for ($i = 1; $i < count($array); ): ?>
<div>
  <!-- something else -->
  <ul>
    <li><?php echo $array[$i++] ?></li> // i == 1, 4, 7, ....
    <li><?php echo $array[$i++] ?></li> // i == 2, 5, 8, ....
    <li><?php echo $array[$i++] ?></li> // i == 3, 6, 9, ....
  </ul>
  <!-- something else -->
</div>
<?php endfor; ?>

But then the above will fail if 2,3 dont exist or 5,6 don't exist, etc.

Update:

This code will work correctly:

<?php

$array = array(0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 0, 11, 22);

for ($i = 1; $i < count($array);): ?>
<div>
  <!-- something else -->
  <ul>
    <?php for($j = 0; $j < 3 && $i + $j < count($array); ++$j):?>
    <li><?php echo $array[$j + $i] ?></li>
    <?php endfor; $i += $j;?> 
  </ul>
  <!-- something else -->
</div>
<?php endfor; ?>

DEMO: http://codepad.org/LFGMkd1G

edited Jun 20, 2020 at 9:12

CommunityBot

11 silver badge

answered Jul 20, 2012 at 18:16

Naftali

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7 Comments

Naftali Over a year ago

@YNT I have the 2nd part working. I am updating and putting DEMO

Naftali Over a year ago

@YNT I updated my answer with a working answer and demo. Please let me know if you need a code explanation.

A. Z. Over a year ago

It works and this is the best explanation. This code is very complicated for me; however, I can copy-past :-).

Naftali Over a year ago

@YNT break it down, bit by bit, I am sure you will get it eventually :-)

A. Z. Over a year ago

I have to because it is very interesting to learn programming.

|

Naftali · Accepted Answer · 2012-07-20 18:14:37Z

1

<?php
$array[0];

for ($i = 0; $i <= count($array); $i + 3) {
?>
<div>
  <!-- something else -->
  <ul>
    <li><? $array[$i + 1] ?></li>
    <li><? $array[$i + 2] ?></li>
    <li><? $array[$i + 3] ?></li>
  </ul>
  <!-- something else -->
</div>
<?php } ?>

The loop you wanted isn't standard, so can only hope it works for you.

Basically it start with $i = 0, and prints $i + 1(= 1), (=2), (=3), next round $i equals 3 ($i + 3), and prints $i + 1(=3+1=4), (=5) , (=6), and so on, until the array reaches its end.

edited Jul 20, 2012 at 18:14

Naftali

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answered Jul 20, 2012 at 13:57

Nadav S.

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2 Comments

Aleks G Over a year ago

Note that with this code you will loose the last one or two elements if the number of elements in the array is not divisible by 3 (e.g. if you have 5 elements, you'll print only the first 3)

A. Z. Over a year ago

@Nadav Thanks for your answer, I'll try to apply this.

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