how would I convert an integer to an array of 4 bytes?
Here is the exact code I want to port (in C#)
int i = 123456;
byte[] ar = BitConverter.GetBytes(i);
// ar will contain {64, 226, 1, 0}
How would I do the exact same thing in PHP ?
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1Are you looking for the result to be an array containing the decimal numbers 64, 226 etc? Or are you actually looking for the bytes, which in PHP would be a string?deceze– deceze ♦2012-07-18 15:36:55 +00:00Commented Jul 18, 2012 at 15:36
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2 Answers
The equivalent conversion is
$i = 123456;
$ar = unpack("C*", pack("L", $i));
You should be aware though that the byte order (little/big endian) is dependent on the machine architecture (as it is also in the case of BitConverter). That might or might not be good.
Comments
Since the equivalent of a byte array in PHP is a string, this'll do:
$bytes = pack('L', 123456);
To visualize that, use bin2hex:
echo bin2hex($bytes);
// 40e20100
// (meaning 64, 226, 1, 0)
4 Comments
user1392060
Might be true. But I still needed the single bytes in a array. Thanks anyway.
deceze
@user
echo $bytes[0], $byte[1], $byte[2], $byte[3]; PHP strings are in essence byte arrays.user1392060
Oh, ok! Excuse my ignorance then. Now that you mention it, I think that I might be overcomplicating things A LOT in PHP...
FluorescentGreen5
@user1392060 If you want single bytes in an array you could try
str_split($bytes).