I'd like to transform a string expecting a dict of parameters to the list of keys of the expected dict, e.g. find f such that:
f("some text %(foo)s %(bar)s") == ['foo', 'bar',] # True
Is there some way to do it ?
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2stackoverflow.com/questions/4839121/…Paolo Bergantino– Paolo Bergantino2012-06-29 14:35:42 +00:00Commented Jun 29, 2012 at 14:35
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2 Answers
Smth like
>>> import re
>>> re.findall("%\(([^\)]+)\)[sif]", "some text %(foo)s %(bar)s", re.M)
['foo', 'bar']
[sif] part can be extended with symbols from table on http://docs.python.org/library/stdtypes.html#string-formatting-operations
Comments
How about this:
>>> S = "some text %(foo)s %(bar)s"
>>> print re.findall(r'%\((.*?)\)', S)
['foo', 'bar']
