Try...catch block doesn't define variable

Question

I have a program, which takes a parameter from the args[] array, defined in the main method, but has a backup in case that isn't defined, in the form of a try...catch block, which, if an ArrayIndexOutOfBounds exception is thrown, instead uses a method called getInt to prompt the user to enter a variable. But, for some reason, when I try to use that variable, my compiler says that it cannot find it. I have the following code:

try {
    int limit = Integer.parseInt(args[0]);
}
catch(ArrayIndexOutOfBoundsException e) {
    int limit = getInt("Limit? ");
}
int[] p = getPrimes(limit);

getPrimes is another method I have, which returns an array of prime numbers starting from 2 and up to a specified number (using the Sieve of Atkin). Anyway, when I write int[] p = getPrimes(limit); and try compiling, it says that the "limit" variable is not defined. Help please!

Francisco Spaeth · Accepted Answer · 2012-06-28 11:25:32Z

8

You should declare it outside the block:

int limit;
try {
    limit = Integer.parseInt(stuff[0]);
}
catch(ArrayIndexOutOfBoundsException e) {
    limit = getInt("Limit? ");
}
int[] p = getPrimes(limit);

answered Jun 28, 2012 at 11:25

Francisco Spaeth

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Jigar Joshi · Accepted Answer · 2012-06-28 11:25:47Z

2

declare limit outside of catch block, currently it is under the scope of catch block catch{}

answered Jun 28, 2012 at 11:25

Jigar Joshi

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Pramod Kumar · Accepted Answer · 2012-06-28 11:27:16Z

2

int limit;
try {
    limit = Integer.parseInt(stuff[0]);
}
catch(ArrayIndexOutOfBoundsException e) {
    limit = getInt("Limit? ");
}
int[] p = getPrimes(limit);

In your program you have created 2 local Limit variable one in try block and another in catch block.

Declare it outside the try block

answered Jun 28, 2012 at 11:27

Pramod Kumar

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Comments

Johnydep · Accepted Answer · 2012-06-28 11:27:50Z

1

Define limit variable outside of try/catch block, you do not have access to variables defined inside try block outside. You would also have to initialize it if you are calling it outside of try block as in your case here.

answered Jun 28, 2012 at 11:27

Johnydep

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