The date time string is in the following format: 06/12/2012 07:21:22. How can I convert it to UNIX timestamp or epoch?
9 Answers
What you're looking for is date --date='06/12/2012 07:21:22' +"%s". Keep in mind that this assumes you're using GNU coreutils, as both --date and the %s format string are GNU extensions. POSIX doesn't specify either of those, so there is no portable way of making such conversion even on POSIX compliant systems.
Consult the appropriate manual page for other versions of date.
Note: bash --date and -d option expects the date in US or ISO8601 format, i.e. mm/dd/yyyy or yyyy-mm-dd, not in UK, EU, or any other format.
8 Comments
+"%s" stands for output format and %s is the format of time in seconds since 1970date --date='06/12/2012 07:21:22 -0000' +"%s" converts UTC date to unix time stampyyyy-mm-dd hh:mm:sshave a look at gnu.org/software/coreutils/manual/html_node/… : gdate --date='2019-06-18 00:02:00 +0000' +%sgdate instead of date. I can run the above command from @Daniel Kamil Kozar using: gdate --date='06/12/2012 07:21:22' +"%s" which in turn gives me: 1339510882For Linux, run this command:
date -d '06/12/2012 07:21:22' +"%s"
For macOS, run this command:
date -jf "%Y-%m-%d %H:%M:%S" "1970-01-01 00:00:00" +%s
8 Comments
-u flag should fix that.date -jf "%Y-%m-%d %H:%M:%S" "2018-01-08 14:45:00" +%sA lot of these answers are overly complicated and also are missing how to use variables. This is how you would do it more simply on standard Linux system (as previously mentioned the date command would have to be adjusted for Mac Users) :
Sample script:
#!/bin/bash
orig="Apr 28 07:50:01"
epoch=$(date -d "${orig}" +"%s")
epoch_to_date=$(date -d @$epoch +%Y%m%d_%H%M%S)
echo "RESULTS:"
echo "original = $orig"
echo "epoch conv = $epoch"
echo "epoch to human readable time stamp = $epoch_to_date"
Results in :
RESULTS:
original = Apr 28 07:50:01
epoch conv = 1524916201
epoch to human readable time stamp = 20180428_075001
Or as a function :
# -- Converts from human to epoch or epoch to human, specifically "Apr 28 07:50:01" human.
# typeset now=$(date +"%s")
# typeset now_human_date=$(convert_cron_time "human" "$now")
function convert_cron_time() {
case "${1,,}" in
epoch)
# human to epoch (eg. "Apr 28 07:50:01" to 1524916201)
echo $(date -d "${2}" +"%s")
;;
human)
# epoch to human (eg. 1524916201 to "Apr 28 07:50:01")
echo $(date -d "@${2}" +"%b %d %H:%M:%S")
;;
esac
}
2 Comments
Just be sure what timezone you want to use.
datetime="06/12/2012 07:21:22"
Most popular use takes machine timezone.
date -d "$datetime" +"%s" #depends on local timezone, my output = "1339456882"
But in case you intentionally want to pass UTC datetime and you want proper timezone you need to add -u flag. Otherwise you convert it from your local timezone.
date -u -d "$datetime" +"%s" #general output = "1339485682"
2 Comments
date formats properly this input.Efficient way to convert date time string to epoch in bash
Avoiding useless repetitives forks, in order to make this translation a lot quicker...
Instead of running 1 fork for each translation, we could run date -f - +%s as background process...
Intro
Common syntax:
epochDate=$(date -d "$InputDate" +%s)
Work fine, but become heavy if run repetetively!
In this post, you will find
- a Quick Demo, following this,
- some Explanations,
- a Function useable for many Un*x tools (
bc,rot13,sed...).
Quick Demo using coproc
coproc DATE { exec stdbuf -o0 /bin/date -f - +%s 2>&1 ;}
echo >&${DATE[1]} 06/12/2012 07:21:22
read -ru${DATE[0]} epochDate
printf 'EPOCH: %u Date:%(%c)T\n' $epochDate $epochDate
EPOCH: 1339478482 Date:Tue Jun 12 07:21:22 2012
About performances, you could compare:
time for i in {1..900};do echo >&${DATE[1]} "now";read -ru${DATE[0]} ans;done
real 0m0.029s
user 0m0.018s
sys 0m0.005s
and:
time for i in {1..900};do ans=$(date +%s -d "now");done
real 0m1.465s
user 0m0.962s
sys 0m0.442s
From more than 1.4 seconds to less than 30 milliseconds!!(on my host).
You could check echo $ans, replace "now" by "2019-25-12 20:10:00" and so on...
Little function
myDate() {
if [[ $1 == -v ]]; then
local -n out=$2
shift 2
else
local out
fi
echo "$*" >&${DATE[1]}
read -ru ${DATE[0]} out
[[ ${out@A} == out=* ]] && echo $out
case $out in ''|*[!0-9]*) return 1;; esac
}
myDate 06/12/2012 07:21:22
1339478482
myDate -v var 06/12/2012 07:21:22
printf '%(%c)T\n' $var
Tue Jun 12 07:21:22 2012
myDate -v var wrong string
printf 'ResultCode: %d: Var: "%s"\n' "$?" "$var"
ResultCode: 1: Var: "/bin/date: invalid date 'wrong string'"
Stop background
You could, once requirement of date subprocess ended:
kill ${DATE_PID}
exec {DATE[1]}>&- ; exec {DATE[0]}<&-
[1]+ Terminated coproc DATE { exec stdbuf -o0 /bin/date -f - +%s; }
Original post (detailed explanation)
Instead of running 1 fork by date to convert, run date just 1 time and do all convertion with same process (this could become a lot quicker)!:
date -f - +%s <<eof
Apr 17 2014
May 21 2012
Mar 8 00:07
Feb 11 00:09
eof
1397685600
1337551200
1520464020
1518304140
Sample:
start1=$(LANG=C ps ho lstart 1)
start2=$(LANG=C ps ho lstart $$)
dirchg=$(LANG=C date -r .)
read -p "A date: " userdate
{ read start1 ; read start2 ; read dirchg ; read userdate ;} < <(
date -f - +%s <<<"$start1"$'\n'"$start2"$'\n'"$dirchg"$'\n'"$userdate" )
Then now have a look:
declare -p start1 start2 dirchg userdate
(may answer something like:
declare -- start1="1518549549" declare -- start2="1520183716" declare -- dirchg="1520601919" declare -- userdate="1397685600"
This was done in only one date subprocess execution!
Using long running subprocess
We just need one fifo:
mkfifo /tmp/myDateFifo
exec 7> >(exec stdbuf -o0 /bin/date -f - +%s >/tmp/myDateFifo)
exec 8</tmp/myDateFifo
rm /tmp/myDateFifo
(Note: As process is running and all descriptors are opened, we could safely remove fifo's filesystem entry.)
Then now:
LANG=C ps ho lstart 1 $$ >&7
read -u 8 start1
read -u 8 start2
LANG=C date -r . >&7
read -u 8 dirchg
read -p "Some date: " userdate
echo >&7 $userdate
read -u 8 userdate
We could buid a little function:
mydate() {
local var=$1;
shift;
echo >&7 $@
read -u 8 $var
}
mydate start1 $(LANG=C ps ho lstart 1)
echo $start1
Or use my newConnector function
With functions for connecting MySQL/MariaDB, PostgreSQL and SQLite...
You may find them in different version on GitHub, or on my site: download or show.
wget https://raw.githubusercontent.com/F-Hauri/Connector-bash/master/shell_connector.bash
wget http://f-hauri.ch/vrac/shell_connector.sh
. shell_connector.bash
newConnector /bin/date '-f - +%s' @0 0
myDate "2018-1-1 12:00" test
echo $test
1514804400
Nota: On GitHub, functions and test are separated files. On my site test are run simply if this script is not sourced. On GitHub, there is no upgrade anymore! Last verified version is on my site!
# Exit here if script is sourced
[ "$0" = "$BASH_SOURCE" ] || { true;return 0;}
5 Comments
time string to UNIX timestamp. My answer address precisely this and offer way to process this operation repetitively, usinf and efficient and system friendly method. Try this for sample: for i in {1..900};do ans=$(date +%s -d "06/12/2012 07:21:22");done using my method, this will take some milliseconds! Addressing POSIX shell and bash-f switch for GNU date usage sample.get_curr_date () {
# get unix time
DATE=$(date +%s)
echo "DATE_CURR : "$DATE
}
conv_utime_hread () {
# convert unix time to human readable format
DATE_HREAD=$(date -d @$DATE +%Y%m%d_%H%M%S)
echo "DATE_HREAD : "$DATE_HREAD
}
1 Comment
I added the following alias to .bashrc (or .zshrc) - note the --utc switch which converts the input as UTC time zone. You can remove it to use the local machine time zone but in my experience I usually want UTC for this:
alias datetoepoch='date --utc +%s -d'
Now I can just type in the terminal something like:
datetoepoch 2024-03-18
and get the result:
1710720000
Comments
Not exactly asked for, but I use this to convert an OpenLDAP timestamp like 20241111073923Z to seconds since the epoch:
echo $(date -u --date=$(echo "$1" | sed \
-e 's/^\(....\)\(..\)\(..\)\(..\)\(..\)\(..\)Z$/\1-\2-\3T\4:\5:\6/') '+%s')
For the example timestamp the command executed will be date -u --date=2024-11-11T07:39:23 +%s, and the output will be 1731310763.
Comments
A bash function is always faster than exec date, here is the code I used to convert datetime to epoch seconds for computing seconds difference between datetimes. However the timezone is ignored, so it's not exactly epoch seconds. While it could be easy to add timezone offset seconds.
if [ "${datetime/ /}" != "$datetime" ]; then
date="${datetime% *}"
time="${datetime##* }"
else
date="${datetime%-*}"
time="${datetime##*-}"
fi
if [ "${date/-/}" != "$date" ]; then
year="${date%%-*}"
s="${date#*-}"
month=$(( 1"${s%%-*}" - 100 ))
day=$(( 1"${s#*-}" - 100 ))
else
year=${date:0:4}
month=$(( 1"${date:4:2}" - 100 ))
day=$(( 1"${date:6:2}" - 100 ))
fi
if [ "${time/:/}" != "$time" ]; then
hour=${time%%:*}
s=${time#*:}
minute=$(( 1"${s%%:*}" - 100 ))
second=$(( 1"${s#*:}" - 100 ))
else
hour=$(( 1"${time:0:2}" - 100 ))
minute=$(( 1"${time:2:2}" - 100 ))
second=$(( 1"${time:4:2}" - 100 ))
fi
month0=$(( month - 1 ))
day0=$(( day - 1 ))
if [ $((year % 100)) == 0 ]; then
leap=$(( year % 400 == 0 ))
else
leap=$(( year % 4 == 0 ))
fi
if [ $leap == 1 ]; then
mo=(31 29 31 30 31 30 31 31 30 31 30 31)
mobase=(0 31 60 91 121 152 182 213 244 274 305 335)
else
mo=(31 28 31 30 31 30 31 31 30 31 30 31)
mobase=(0 31 59 90 120 151 181 212 243 273 304 334)
fi
days_1970=$(( 1970 * 365 + 1970 / 4 - 1970 / 100 + 1970 / 400 ))
days_0=$(( year * 365 + year / 4 - year / 100 + year / 400 ))
epochday=$(( days_0 - days_1970 + mobase[month0] + day0 ))
epochsec=$(( epochday * 86400 + (hour * 60 + minute) * 60 + second ))