PHP - Variable in a static method name [duplicate]

Question

Possible Duplicate:
PHP Using a variable when calling a static method

I've read through a few different posts on here (I.E. PHP Using a variable when calling a static method) when trying to use a variable on a static function, but I just can't seem to get the call_user_func_array() function to work the same as if I was able to call the variable directly in the class name.

PHP >= 5.3.0 Method:

$data = $factory_model::by_array(array(
    $form_fields['name_field']  => $value
));

PHP < 5.3.0 Method:

$data = call_user_func_array(array($factory_model, 'by_array'), array(  
    $form_fields['name_field']  => $value
));

It's some code that I've inherited so I can't change that much on the models, but it should give the following output:

initiative_forecast_type Object
(
    [id:initiative_forecast_type:private] => 0
    [forecast_type:initiative_forecast_type:private] => TRTR
    [tstamp] => 2012-06-11 12:52:07
)

Which it does using the standard PHP 5.3 Method (My user input/value was 'TRTR')

But if I use the call_user_func_array method I get:

initiative_forecast_type Object
(
    [id:initiative_forecast_type:private] => 0
    [forecast_type:initiative_forecast_type:private] => 
    [tstamp] => 2012-06-11 12:52:07
)

So it's not setting the 'forecast_type' field. I've uploaded the model here - http://pastebin.ca/2160201

For reference - $factory_model = initiative_forecast_type_factory

I thought the 2 call_user_func_array() function should work the same as the 5.3.0 method, but it doesn't seem to be - Can anyone point me in the right direction?

Thanks! Christian

Hmm you should wrap the array in another array when you do call_user_func_array() I think, i.e. the second argument — Ja͢ck
– Ja͢ck, Commented Jun 11, 2012 at 12:24

lanzz · Accepted Answer · 2012-06-11 12:08:10Z

3

call_user_func_array() expects the second parameter to be an array of the actual arguments for the function (the keys in the array would be disregarded). What you actually want is call_user_func().

call_user_func_array('func', array('foo' => 'bar')) === func('bar')
call_user_func_array('func', array(array('foo' => 'bar'))) === func(array('foo' => 'bar'))
call_user_func('func', array('foo' => 'bar')) === func(array('foo' => 'bar'))

answered Jun 11, 2012 at 12:08

lanzz

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1 Comment

christian.thomas Over a year ago

Ahhhh… That's the one… call_user_func with the same parameters worked perfectly - Thanks!

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