Checking an array for an array? [duplicate]

Question

I am putting an array ($row) in another array ($allRows):

array_push($allRows, $row);

Is there an easy way to check if an array already exists in $allRows?

What do you mean? array_intersect?

hakre
– hakre

2012-05-30 12:47:09 +00:00
Commented May 30, 2012 at 12:47 — hakre
– hakre, Commented May 30, 2012 at 12:47

elo · Accepted Answer · 2012-05-30 12:42:23Z

2

Yes:

if (in_array($array1, $array2)) {
echo "Array found";
}
// $array1 - needle.

answered May 30, 2012 at 12:42

elo

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1 Comment

EOB Over a year ago

That does the trick, thanks! Perfect...didnt know that in_array can do that.

hakre · Accepted Answer · 2012-05-30 12:52:06Z

1

This is possible with in_array^Docs:

if (in_array($row, $allRows, TRUE)) {
   echo "Array found";
}

In difference to the existing answer, this one actually tells you the order of parameters and that it's necessary that you specify the strict parameter.

Otherwise you would be comparing something else which most likely is not what you're looking for, see Comparison Operators^Docs.

answered May 30, 2012 at 12:52

hakre

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Comments

alex · Accepted Answer · 2012-05-30 12:40:07Z

0

Use in_array()...

$range = range(1, 10);

var_export(in_array($range, array(range(1, 10))));

CodePad.

answered May 30, 2012 at 12:40

alex

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Comments

Ras · Accepted Answer · 2012-05-30 12:40:31Z

0

You can check if $allRows already have elements with

count($allRows)

answered May 30, 2012 at 12:40

Ras

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