Defining an array object property

Question

I have a class which creates an object. Ten of these objects are then placed in an array via a for() loop. Within the class is an if() statement defining click movement and whether the user is clicking on an object or empty space:

if (distance < this.properties.radius) {
    removeEnabled = true;
    this.manageClick();
} else {
    removeEnabled = false;
    this.properties.alpha = 0;
}

What code would I have to use to discover whether an item within the array has removeEnabled = true or if it has removeEnabled = false? Then perform separate functions for if it is true and or if it is false?

wong2 · Accepted Answer · 2012-05-08 11:17:57Z

1

You could just add that removeEnabled property to your object:

obj.removeEnabled = true/false;

then you can read the obj from the array and check its removeEnabled property

answered May 8, 2012 at 11:17

wong2

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Comments

Daniel van Dommele · Accepted Answer · 2012-05-08 11:18:13Z

1

if you set

removeEnabled = true

to

this.removeEnabled = true

it is set as a property of the object and then in your forloop you simply do this:

for (var i = 0; i < objects.length; i++) {
   if (objects[i].removeEnabled) {
       // enter required code
   }
}

answered May 8, 2012 at 11:18

Daniel van Dommele

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3 Comments

Jon_091 Over a year ago

this only acts on the last added object... I it to recognise if one of the objects in the array has removeEnabled = true then something happens

Daniel van Dommele Over a year ago

What exactly do you mean? setting the this.removeEnabled in the if statement is in the constructor code of the class right? so when you are checking the array and you check of the current object (objects[i]) if it has removeEnabled == true, then that should work for each object and not only the last. Do you otherwise have a link to your full code?

JamieJag Over a year ago

I think Daniel's answer makes a lot of sense. If you could provide more information around the "class" and the "objects" it creates, then we may be able to provide a better answer

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