Globalize variables in php

Question

I have 2 files. Lets say :

first.php

$a = 'blah';
echo 'echo2='.$a;

function foo(){
global $a;
echo 'echo3='.$a;
return $a;
}

second.php

require_once(path/to/the/file/first.php);
echo 'echo='.$a;
$b = foo();
echo 'echo4='.$b;

running the second.php file I get the following output :

echo=blah
echo2=blah
echo3=
echo4=

My question is "why I can't access variable $a in the function foo !

There's also the syntax error with the require_once. If you don't give the exact code, you'll only get guesses, not answers. Specifically if the include occurs within a functions local variable scope, the $a= declaration won't be global. — mario
– mario, Commented Apr 27, 2012 at 17:20
the register_globals in php.ini is set to off. Thanks for your answers! — Reaver
– Reaver, Commented Apr 27, 2012 at 17:31

Brad · Accepted Answer · 2012-04-27 17:13:59Z

3

Change $global to global. That should fix it.

answered Apr 27, 2012 at 17:13

Brad

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Comments

TigerTiger · Accepted Answer · 2012-04-27 17:16:12Z

1

or use

 $GLOBALS["Your_var_without_dollar_sign"];

answered Apr 27, 2012 at 17:16

TigerTiger

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