I want to handle 2 cases:
(string)->string@string otherStuff->string
how can it be done?
-
4"What have you tried?" Did it work? If not, why not?user166390– user1663902012-04-23 01:10:40 +00:00Commented Apr 23, 2012 at 1:10
-
why was this downgraded?Itzik984– Itzik9842012-04-23 01:26:00 +00:00Commented Apr 23, 2012 at 1:26
Add a comment
|
3 Answers
>>> re.search(r'\(([^)]+)\)|@([^ ]+) ', '(string)').groups()
('string', None)
>>> re.search(r'\(([^)]+)\)|@([^ ]+) ', '@string otherStuff').groups()
(None, 'string')
answered Apr 23, 2012 at 1:05
Ignacio Vazquez-Abrams
804k160 gold badges1.4k silver badges1.4k bronze badges
Comments
import re
def getstring(string):
testforstring = re.search("\((.*)\)",string)
if testforstring:
return testforstring.group(1)
testforstring = re.search("@(.*?)\s+.*",string)
if testforstring:
return testforstring.group(1)
return None
Allows you to do:
>>> print getstring('(hello)')
hello
>>> print getstring('@hello sdfdsf')
hello
Comments
Will this work for you?
In [45]: s='(string)'
In [46]: s = s[1:-1]
In [47]: s
Out[47]: 'string'
and
In [48]: s = '@string otherstuff'
In [49]: s=' '.join(s.split()[1:])
In [50]: s
Out[51]: 'otherstuff'
