Detect if a string is in a multi-dimensional array in PHP

Question

I have an array that looks like this:

Array
(
[0] => Array
(
    [Product] =>  Amazing Widget
    [Value] => 200
)

[1] => Array
(
    [Product] => Super Amazing Widget
    [Value] => 400
)

[2] => Array
(
    [Product] =>  Promising Widget 
    [Value] => 300
)

[3] => Array
(
    [Product] => Superb Widget
    [Value] => 400
)
)

I believe it's a nested Multi-dimensional array.

Anyway I'm trying to detect if a Product Name Already exists in the array. This is what I'm trying to do

if('Super Amazing Widget' is in the array) {
    echo 'In the Array';
}

I've tried this:

if(in_array('Super Amazing Widget', $array)){
    echo 'In The Array';
}

But it's not working and I can't find out why.

EDIT:

Some of the Functions in here worked really well: in_array() and multidimensional array

in_array won't work the way you want on this array, see stackoverflow.com/questions/4128323/… — John Flatness
– John Flatness, Commented Apr 16, 2012 at 20:04

Alex Turpin · Accepted Answer · 2012-04-16 20:08:00Z

4

in_array will not do a recursive search, ie, search in sub-arrays. You'll need to loop through your array and manually check for your value.

$found = false;
foreach($arr as $item) {
    if ($item['Product'] == 'Super Amazing Widget') {
        $found = true;
        break;
    }
}
if ($found)
    echo 'found!'; //do something

Live example

edited Apr 16, 2012 at 20:08

answered Apr 16, 2012 at 20:00

Alex Turpin

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2 Comments

Talon Over a year ago

I was just editing that, was a typo in the question. The problem is still there.

Alex Turpin Over a year ago

@Talon let me cook up another answer.

kuba · Accepted Answer · 2012-04-16 20:04:02Z

0

foreach ($array as $item) {
    if ($item["Product"] == "Super Amazing Widget") {
        echo "in the array";
        break;
    }
}

answered Apr 16, 2012 at 20:04

kuba

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Comments

anubhava · Accepted Answer · 2012-04-16 20:12:22Z

0

This is without using a loop:

$filt = array_filter($array, create_function('$val',
                                'return $val["Product"] === "Super Amazing Widget";'));
if (!empty($filt)) {
    echo "In The Array\n";
}

answered Apr 16, 2012 at 20:12

anubhava

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Comments

Clay Hinson · Accepted Answer · 2012-04-16 21:04:26Z

0

using array_filter similar to a previous answer, but using the newer anonymous function instead of the older create_function():

if(array_filter(
    $array, 
    function($val) { return $val['Product'] === 'Super Amazing Widget'; }
    )) {
    echo 'In the array' . PHP_EOL;
}

answered Apr 16, 2012 at 21:04

Clay Hinson

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