Pass local variables in a vimscript function to python

Question

For example, I want to use default arguments:

function! MakeOrgTable(...)
let l:num_col = a:0 > 0? (a:0) :  0;
python << EOF
import vim
vim.current.buffer[:]=make_table(vim.current.buffer, vim.eval("l:num_col"))
EOF
endfunction

But it doesn't work, Vim cannot find l:num_col. But I do not want define a global variable like g:num_col.

So is there a way to pass local variables in a vimscript function to Python?

I use neovim 0.8.0.

Is the solution proposed addressing your problem? How can we help you more? — Vivian De Smedt
– Vivian De Smedt ♦, Commented Feb 12, 2023 at 17:41
@VivianDeSmedt Thank you! Your answer is the solution. I'm sorry that I procrastinated. — Tokubara
– Tokubara, Commented Feb 13, 2023 at 14:41
Thanks for the feedback :-) No worries I was just verifying that your need were understood. — Vivian De Smedt
– Vivian De Smedt ♦, Commented Feb 13, 2023 at 15:54

Vivian De Smedt · Accepted Answer · 2023-02-04 13:47:57Z

1

I believe the problem is related to trailing ; in the definition of l:num_col

I would do:

function! MakeOrgTable(...)
let l:num_col = a:0 > 0 ? (a:0) : 0
python << EOF
import vim
vim.current.buffer[:]=make_table(vim.current.buffer, vim.eval("l:num_col"))
EOF
endfunction

Another problem is that the method make_table is not defined.

edited Feb 4, 2023 at 13:47

answered Feb 4, 2023 at 13:36

Vivian De Smedt♦

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