I have this this String
22<>22
And i have this list
test
dev
too
The output should be like
22test22
22dev22
etc..
This is the commands i use for do that
cat list | sed 's/$/22/g' | sed 's/^/22/g'
The command i use for do that
cat list | sed 's/$/22/' | sed 's/^/22/'
But it doesn't helpful Because i have big list of
22<>22
3<>33
134423<>4
You can assign to an array the list of strings that will replace to <>.
In a file called list.txt you should have:
test
dev
too
And in a file called data.txt you should have:
22<>22
3<>33
134423<>4
Solution 1:
Reading the file list.txt and assign its content to an array.
Read array using bash
export IFS=$'\n'
readarray array < list.txt
Read array using zsh
array=("${(@f)"$(<list.txt)"}")
Finally you have to iterate over array variable to get each element of the list and replace with sed:
for i in ${array[@]}; do
sed "s/<>/$i/g" data.txt
done
Note: The for loop will print the text to the stdout (in your terminal). But if you want to redirect the output to a file, you can use > after done keyword:
for i in ${array[@]}; do
sed "s/<>/$i/g" data.txt
done > final.txt
This solution will produce an output like this:
22test22
3test33
134423test4
22dev22
3dev33
134423dev4
22too22
3too33
134423too4
Solution 2:
First you will have to read the file list.txt and assign its content to an array.
Read array using bash
export IFS=$'\n'
readarray array < list.txt
Read array using zsh
array=("${(@f)"$(<list.txt)"}")
After that you have to iterate over each line of file data.txt and inside that loop read each item from the array to apply the sed command:
while read line ; do
for i in ${array[@]}; do
sed "s/<>/$i/g" <<< "$line"
done
done < data.txt
Or redirecting the stdout to a file:
while read line ; do
for i in ${array[@]}; do
sed "s/<>/$i/g" <<< "$line"
done
done < data.txt > final.txt
This solution will produce the following output:
22test22
22dev22
22too22
3test33
3dev33
3too33
134423test4
134423dev4
134423too4
change <> to one character | delimiter:
$ sed -s 's/<>/|/g' asdf1 > asdf2
$ cat asdf2
22|22
3|33
134423|4
combine 2 files into one file, using same one character | delimiter:
$ paste -d"|" asdf asdf2 > combined
$ cat combined
test|22|22
dev|3|33
too|134423|4
split with |, and print in order:
$ awk -F'|' '{print $2 $1 $3}' combined
22test22
3dev33
134423too4
So, in summary:
sed -s 's/<>/|/g' asdf1 > asdf2
paste -d"|" asdf asdf2 > combined
awk -F'|' '{print $3 $1 $2}' combined
But this will only works, if there is only 1 <>placeholder in each line.
With zsh, assuming list doesn't contain $, ` nor \ characters:
$ cat list
22<>22
3<>33
134423<>4
$ cat data
test
dev
too
$ () {print -rC1 -- ${(e)${(f)"$(<list)"}//'<>'/'$^@'}; } ${(f)"$(<data)"}
22test22
22dev22
22too22
3test33
3dev33
3too33
134423test4
134423dev4
134423too4
Where we pass the non-empty lines of data as arguments to an anonymous function. Within that function, we replace <> with $^@ in the lines of list, so we end up with 22$^@22 3$^@33, and with the expand parameter expansion flag, the expansions in there are performed, where $^@ is like $@ (the list of arguments) except that the array expansion is rc/fish-like instead of csh-like (with a=(1 2 3), before${^a}after expands to before1after before2after before3after instead of before1 2 3after with before${a}after).
-f