.bashrc path problems

It looks like you will have to either add each directory that contains an executable separately or link all executables to the same directory.

1. Add all directories manually.

   First, collect the list of relevant directories (I am assuming you are running Linux or, in any case, that you have GNU tools):

   find /home/cs/Id -type f -executable -exec dirname {} + | sort -u
   

   The above will find all executable files in /home/cs/Id and print the name of the directory containing them. The sort -u ensures that each directory is only printed once. I created a few test directories, so on my system I get:

   $ find /home/terdon/Idl/ -type f -executable -exec dirname {} + | sort -u
   /home/terdon/Idl/foo/bar/bag/ho
   /home/terdon/Idl/foo/bar/bag/ho/fa/fe/re
   /home/terdon/Idl/foo/bar/baz/foo/bar
   /home/terdon/Idl/foo/bar/baz/foo/bar/baz/foo/bar/baz
   

   Now, you want to get these into the right format for adding to $PATH:

   $ find /home/terdon/Idl/ -type f -executable -exec dirname {} + | sort -u | tr '\n' ':'
   /home/terdon/Idl/foo/bar/bag/ho:/home/terdon/Idl/foo/bar/bag/ho/fa/fe/re:/home/terdon/Idl/foo/bar/baz/foo/bar:/home/terdon/Idl/foo/bar/baz/foo/bar/baz/foo/bar/baz:
   

   Copy that (excluding the final :) and add it to your PATH:

   PATH="$PATH:/home/terdon/Idl/foo/bar/bag/ho:/home/terdon/Idl/foo/bar/bag/ho/fa/fe/re:/home/terdon/Idl/foo/bar/baz/foo/bar:/home/terdon/Idl/foo/bar/baz/foo/bar/baz/foo/bar/baz"
   

2. Find all executable files and symlink them to a directory already in your PATH.

   find /home/terdon/Idl/ -type f -executable -exec ln -s {} ~/bin \;
   

   On some Linux systems (Ubuntu, for example) the ~/bin directory is automatically added to your PATH if it exists. If this doesn't happen on your system, add it yourself:

   PATH="$PATH:/home/cs/bin"
   

I think one has to enumerate the directories, then. This generates the line for you automatically:

#!/usr/bin/python3
# -*- coding: utf-8 -*-

# Copyright © 2016 Martin Ueding <[email protected]>
# Licensed under the MIT license

import argparse
import os


def main():
    options = _parse_args()

    additions = []

    for base in options.base:
        for dirpath, dirnames, filenames in os.walk(base):
            additions.append(dirpath)

    line = ':'.join(additions)

    if options.short:
        print(line)
    else:
        print('PATH=$PATH:'+line)


def _parse_args():
    parser = argparse.ArgumentParser(description='')
    parser.add_argument('base', nargs='+', help='Basepath')
    parser.add_argument('--short', action='store_true')
    options = parser.parse_args()

    return options


if __name__ == '__main__':
    main()

Save that snippet as /usr/bin/path-recurse and apply chmod +x /usr/bin/path-recurse. Then you can use it in your prompt either to generate the line with path-recurse /tmp /foobar … and it will give you the Bash line:

PATH=$PATH:/tmp:/tmp/kde-muIusrrC:/tmp/vs0cOIg:/tmp/.esd-1000:/tmp/ssh-oGWOvuUnyqPF:/tmp/.Test-unix:/tmp/.font-unix:/tmp/.XIM-unix:/tmp/.ICE-unix:/tmp/.X11-unix 

Alternatively you can use the following in your .bashrc:

PATH=$PATH:$(path-recurve /tmp /foobar …)

This will then dynamically go through all the folders whenever the .bashrc is sourced.

I think I have solved my problem. All I did in my .bashrc file I wrote:

PATH=${PATH}:$(find ~/Idl -type d | tr '\n' ':' | sed 's/:$//')

Then: > source .bashrc

Now I am able to run all programs and scripts inside various sub-directories under my main Idl directory.

Thanks all for your kind attentions.