Not sure why I am getting this. I realize this must be a common question, but can't figure it out.
#!/bin/bash
#Checks word count of each text file directory and deletes if less than certain amount of words
#Lastly, displays number of files delter
count = 0 #Set counter to 0
limit = 2000
for file in *.txt
do
words = wc -w > $file
if words < $limit
rm $file
count = $count + 1
end
end
print "Number of files deleted: $count"
I'm afraid your script is full of syntax errors. The specific error you are seeing is because you're not closing the for loop correctly, but there are many, many more:
= when assigning values to variables (except in arithmetic expressions);var=`command` or var=$(command);$var, not var and generally, that needs to be quoted ("$var");-lt of the [ command, not < unless you're using double parentheses;command > file format will overwrite file with the output of command. You probaly meant to use wc < "$file" and not wc > $file;var=$var+1 unless that variable has been previously declared as an integer, you need ((var=var+1)), var=$((var+1)) or declare -i var; var=var+1. For adding 1, you can also use ((var++));ifsyntax is wrong. The right format is if condition; then do something; fifor loop, the right syntax is for loop-specification; do something; done;print command (not built in bash anyway), only printf and echo;So, a working version of your script with slight improvements, would be:
#!/bin/bash -
# Checks word count of each text file directory and deletes if less than certain amount of words
# Lastly, displays number of files deleted
count=0 # Set counter to 0
limit=2000
for file in *.txt
do
words=$(wc -w < "$file")
if [ "$words" -lt "$limit" ]
then
rm -- "$file"
((count++))
fi
done
echo "Number of files deleted: $count"
Next time, I recommend you familiarize yourself with a language before attempting to code in it. Each language has its own rules and syntax.
((var++)) over let var++?
((...)).
if ((words < limit)) then? @StéphaneChazelas
[ "$words" -lt "$limit" ] and count=$((count + 1)) so it can be a standard sh script as there's no need for bash here.
Your loop terminators are incorrect. A for loop is terminated by done, not end. Likewise, the if condition is terminated by fi, not by end.
This is Bourne/POSIX-family shell syntax. Other shells may indeed have those two things terminated by end, but bash does not.
words = wc -w > $file
the > char here seems out of place. Without it you would be counting the lines of $file but as it stands you are counting the line of stdin and outputting the result in $file.
cshinstead.