Writing a javascript function which accepts a single array argument [duplicate]

Question

Please write a function called lastElement which accepts a single array argument. The function should return the last element of the array (without removing the element). If the array is empty, the function should return null.

lastElement([3,5,7]) //7
lastElement([1]) //1
lastElement([]) //null

** the code that I wrote **

let array = [3, 5, 7];

function lastElement (array) { 
    return array[array.length - 1];
}

I'm flummoxed on the last part with the function returning null if the array if empty.

You are writing a new question on Stackoverflow just to ask "How do I know if an array is empty"? :| — Jeremy Thille
– Jeremy Thille, Commented Nov 24, 2020 at 15:19
Don't let downvotes grind you down. Either you didn't know (in which case you're in the right place) or you had a mental block, in which case you're in the right place. :-) — JSmart523
– JSmart523, Commented Nov 24, 2020 at 15:32
If you want the easiest for beginners : function lastElement(array){ if(array.length === 0){ return null } else { return array[array.length - 1] } } — Yonas Tesh
– Yonas Tesh, Commented Oct 8, 2021 at 15:04

Thejool · Accepted Answer · 2020-11-24 15:20:51Z

3

You can update your code a tiny bit to check if the array is empty and then return null like this:

return array.length ? array[array.length - 1] : null;

answered Nov 24, 2020 at 15:20

Thejool

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