php variable scope

Question

i'm confused about the php variable scope. such as:

while(true){
    $var = "yes , it is a test!";
  }
  printf($var)

the $var is defined in while statement scope , how could we get it outside it's scope ? and i can't find explanation on the document .

i wonder how php deal with it's scope .

Please go back and review your old questions. If there are good sollutions, mark them as accepted using the green 'check'. If there are none (which i doubt), please consider answering your own questions with how you solved the problems in the end. Furthermore, try and check your formatting. — Nanne
– Nanne, Commented Apr 12, 2011 at 7:52
This might be a useful starting point: php.net/manual/en/language.variables.scope.php — Will Vousden
– Will Vousden, Commented Apr 12, 2011 at 7:53
how about switch() case statement? Does it create its own scope like a function? Thanks~ — user798033
– user798033, Commented Oct 23, 2011 at 21:21
if you want to create a new local scope stackoverflow.com/a/33460057/3160597 — azerafati
– azerafati, Commented Nov 1, 2015 at 7:21

S L · Accepted Answer · 2011-04-12 07:51:20Z

8

while is not a function. scope of variable refers to variable inside functions and classes

answered Apr 12, 2011 at 7:51

S L

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Comments

Ikke · Accepted Answer · 2011-04-12 07:52:12Z

6

In PHP, a while loop doesn't create a new scope. So it will be available in the function

answered Apr 12, 2011 at 7:52

Ikke

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Nanne · Accepted Answer · 2011-04-12 07:54:32Z

3

If you do while(true) you will not get out of the while, so it wouldn't matter. But if you would have a real expression, something like this (this is a useless example, i know)

$i=0
while($i<10){ 
   $var = "yes , it is a test!"; 
   $i++;
 } 
 printf($var);

Will just work. There is no special "while" variable scope, the printf will print your string. check : http://php.net/manual/en/language.variables.scope.php

answered Apr 12, 2011 at 7:54

Nanne

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Shakti Singh · Accepted Answer · 2011-04-12 07:50:48Z

2

Loop does not have any scope in PHP. variable is simply available outside the loop.

just echo outside the loop;

echo $var;

answered Apr 12, 2011 at 7:50

Shakti Singh

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qbert220 · Accepted Answer · 2011-04-12 07:53:33Z

0

For the complete answer check the documentation:

http://php.net/manual/en/language.variables.scope.php

answered Apr 12, 2011 at 7:53

qbert220

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davidS · Accepted Answer · 2013-08-03 23:02:26Z

0

Notice: Different PHP-version behave differently on $GLOBALS, $_SERVER ($HTTP_SERVER_VARS [deprecated]) and $_SESSION. Please check that. Old PHP page are not always upwards compatible. You should check that.

answered Aug 3, 2013 at 23:02

davidS

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