Detecting JavaScript errors

Question

I am trying to figure out why a page is not working correctly in Internet Explorer 7.

I get a JavaScript error that says

error is on line 1958 char 7

My HTML code is only 534 lines with all of my JavaScript code externally linked.

How do I go about finding this error?

Does this error put all of the external files in the file which makes the number of lines more than my HTML code?

Would this be what I need to do to figure out where the error is in the JavaScript code?

The problematic code looked like it was coming from jQuery 1.4.2 min so I went and went with a newer version and the error has gone away. — pertrai1
– pertrai1, Commented Apr 11, 2011 at 19:02

Mike Lewis · Accepted Answer · 2011-04-11 17:55:12Z

2

You should use Internet Explorer Developer Toolbar. It is extremely useful for debugging JS in IE.

I've also heard good things about Web Development Helper. (It even supports IE6!)

If you have Visual Studio, I would enabling script debugging in Advanced options. That may yield better debugging.

edited Apr 11, 2011 at 17:55

answered Apr 11, 2011 at 17:43

Mike Lewis

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2 Comments

pertrai1 Over a year ago

I have been using that and all is working fine in IE 8 & 9. It is something that is messed up in 7 and below and I don't understand how it can tell me it is online 1958 when there are only 534 lines in my page?

Mike Lewis Over a year ago

I feel your pain, IE is absolutely terrible at JS errors and often points to the wrong line! (And in your case, a line that doesn't even exist).

Jonathan · Accepted Answer · 2011-04-11 17:44:18Z

0

My first instinct would be to try the site in Firefox and have a look at it with the Firebug plugin. I'm not sure what kind of debugger support is available in IE.

answered Apr 11, 2011 at 17:44

Jonathan

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James Kyburz · Accepted Answer · 2011-04-11 17:49:37Z

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After installing Internet Explorer Developer Toolbar

window.onerror = function myErrorHandler(errorMsg, url, lineNumber) {
  debugger;
  console.log(errorMsg, url, lineNumber);
};

answered Apr 11, 2011 at 17:49

James Kyburz

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