Suppose I have the following dictionary.
params = {'a': 'aaa', 'b': 'bbb', 'c': 'ccc', 'd': 'ddd-hoge'}
When printing using the following script,
>>> print("1: {a} 2: {b} 3: {c} 4: {d}.split('-')[0]".format(**params))
the output will be
"1: aaa 2: bbb 3: ccc 4: ddd-hoge.split('-')[0]"
How should I modify the script to get the same output as the following?
"1:aaa 2:bbb 3:ccc 4:ddd"
This seems to work:
params = {'a': 'aaa', 'b': 'bbb', 'c': 'ccc', 'd': 'ddd-hoge'}
print("1: {a} 2: {b} 3: {c} 4: {d}".format(**{
k: v.split('-')[0] for k, v in params.items()}))
This does the processing on the dict, and then formats for print.
1: aaa 2: bbb 3: ccc 4: ddd
Just simply split afterward:
print("1: {a} 2: {b} 3: {c} 4: {d}".format(**params).split('-')[0])
An operation of that complexity won't be handled by the formatting mini language. You would have to do the transformation externally.
One way would be to make a copy of the dictionary and update the particular value you want:
p = params.copy()
p['d'] = params['d'].split('-')[0]
print("1: {a} 2: {b} 3: {c} 4: {d}".format(**p))
You could of course modify params in place as well. A more elegant solution might be to apply the transformation to all the values:
print("1: {a} 2: {b} 3: {c} 4: {d}".format(**{k: v.split('-')[0] for k, v in params.items()}))
[0]?AttributeError: 'str' object has no attribute 'split('-')'is thrown