How do I test for multiple .includes with Array.includes() in my if statement? The below seems to work on one item, ie. slug-title-one but ignores the second.
if (item.slug.includes('slug-title-one' || 'slug-title-13')) {
// checks for and displays if either
}
As the documentation the Array.includes can only test for a single element.
You could reverse your logic though and use
if (['slug-title-one','slug-title-13'].some(slug => item.slug.includes(slug))) {
// checks for and displays if either
}
item.slug is null.if in another one the does if (item.slug) {...} . Btw this problem would exist in your original attempt as well.You have a few options. Here are some ideas:
Repeat includes
if (item.slug.includes('slug-title-one') || item.slug.includes('slug-title-13')) { ... }
Helper function
if( includes(item.slug, 'slug-title-one', 'slug-title-13') ) { ... }
function includes() {
var args = Array.prototype.slice.call(arguments);
var target = args[0];
var strs = args.slice(1); // remove first element
for(var i = 0; i < strs.length; i++) {
if(target.includes(strs[i])) {
return true;
}
}
return false;
}
Array.includes which means the item.slug is an array. So the regex version wouldn't work.
||evaluates the first string as truthy and so that is what is passed toincludes(). You have to check both separately. Read the documentation for includes()['slug-title-one','slug-title-13'].reduce( (a, b) => a && item.slug.includes(b), true)