Undefined Javascript variable

Question

So here is the problem. There is a HTML/JS code, but I can't read v3 variable. In short anything after DDDD(D,{"COM":"lng","leaf":145,"AXIS":true}); (which is some kind of predefined random array) is unreadable(or ignored as JS code). Why? And how can i get contents of v3? Is this a javascript parse bug?

<html>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<head>
<script type="text/javascript">
  <!--
  var v1 = 12345;
  var v2 = "Hello world";
  DDDD(D,{"COM":"lng","leaf":145,"AXIS":true});
        var v3 = "World Hello!!!"; 
  //-->
</script>
</head>

<!-- some html code -->
<script>

alert("This is "+v3);

</script>

<!-- some html code -->
</html>

Where DDDD is defined? Do you have it in some other file that's loaded before this particular snippet? — Juho Vepsäläinen
– Juho Vepsäläinen, Commented Jan 2, 2011 at 13:29
"which is some kind of predefined random array" - I think you just forgot to include this predefined stuff. :) — bzlm
– bzlm, Commented Jan 2, 2011 at 13:33

user113716 · Accepted Answer · 2011-01-02 13:35:14Z

4

Your first script crashes because you don't have a DDDD function, so the v3 never gets assigned.

You refer to the DDDD line as "which is some kind of predefined random array". It's not.

It is an attempt to call a function, and pass it two arguments.

DDDD() a function call.
a D variable argument.
a {"COM":"lng","leaf":145,"AXIS":true} object literal argument.

edited Jan 2, 2011 at 13:35

answered Jan 2, 2011 at 13:29

user113716

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1 Comment

Fontfaced Over a year ago

It's ok guy's, i just realise i forgot to include some remote script src. Thanks :)

T.J. Crowder · Accepted Answer · 2011-01-02 13:30:13Z

1

I assume that D and DDDD are defined somewhere? Your code excerpt doesn't define them. If they're defined, I'm not seeing the error; if they aren't, well, that's your problem.

answered Jan 2, 2011 at 13:30

T.J. Crowder

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Seldaek · Accepted Answer · 2011-01-02 13:30:53Z

1

Your problem is that the DDDD() line throws an exception because it uses an undefined function (DDDD is not defined), then anything that follows inside that script tag is not executed. The second script tag is executed however, but it doesn't have access to the variable that was never defined.

answered Jan 2, 2011 at 13:30

Seldaek

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user447356 · Accepted Answer · 2011-01-02 13:40:21Z

1

You can catch errors and then v3 will come out fine:

<script type="text/javascript">
      <!--
      var v1 = 12345;
      var v2 = "Hello world";
      try {
         DDDD(D,{"COM":"lng","leaf":145,"AXIS":true});
      }
      catch (ex) {
         alert("error: " + ex.message);
      }
      var v3 = "World Hello!!!"; 
      alert(v3);
      //-->

</script>

answered Jan 2, 2011 at 13:40

user447356

Comments

Tasawer Khan · Accepted Answer · 2011-01-02 13:29:35Z

0

There is an error at line

DDDD(D,{"COM":"lng","leaf":145,"AXIS":true});

When an error occurs. Remaining JS is not executed.

answered Jan 2, 2011 at 13:29

Tasawer Khan

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elasticrash · Accepted Answer · 2011-01-02 13:32:35Z

0

When javascript gets an error in a line (depends the egine) it either breaks or fails to load entirely. And like most people already said before me, the DDDD() has to exist somewhere else is undefined.

answered Jan 2, 2011 at 13:32

elasticrash

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