PHP: Returning function value by itself not working

Question

I have a function inside of a class, every time I use I got error undefined function in_array_r() inside of foreach. But when I use it outside of the class as normal function it works. I want to use this inside of the class so I will not call in every page.

public function in_array_r($needle, $haystack, $strict = false) {
        foreach ($haystack as $item) {
            if (($strict ? $item === $needle : $item == $needle) || (is_array($item) && in_array_r($needle, $item, $strict))) {
                return true;
            }
        }
        return false;
    }

Nathan Dawson · Accepted Answer · 2017-05-04 03:08:11Z

1

The function is recursive - it's calling itself. When you put it inside a class (as a method), you need to update the reference to in_array_r() within the method body.

This:

. . .(is_array($item) && in_array_r($needle, . . .

Becomes:

. . .(is_array($item) && $this->in_array_r($needle, . . .

answered May 4, 2017 at 3:08

Nathan Dawson

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Comments

nfproductions · Accepted Answer · 2017-05-04 03:09:33Z

1

You need to assign the method to the object.

$this->in_array_r();

answered May 4, 2017 at 3:09

nfproductions

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1 Comment

zeflex Over a year ago

also you can improve your code and return false if $haystack false, as a simple check.

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