Replace on Array In Jquery without using loop

Question

I have a array on Jquery that have some values .Now i want to replace a character from all the items in the array if it have in the array.

var arrayData = [
       "Safi Landmark Hotel and Suites",
       "Safi Landmark Hotel Suites",
       "Safi Landmark Hotel and Suites"
];

This is my array now i want to replace 'and' from the items with '&' .How can we do this without using loop.

Whatever mechanism you use, it will use an iterator inside to go through each item. Is this a matter of syntax? — Roland Mai
– Roland Mai, Commented Sep 24, 2014 at 6:26
That is our question also, how we can do this without using a loop !!! — Diode
– Diode, Commented Sep 24, 2014 at 6:27

user3627944 · Accepted Answer · 2014-09-24 06:33:49Z

1

Try this code with map for search and replace:

var testdata = $.map( [ 'a&b', 'abcz&mz', 'test' ], function( abc ) {
        return abc.replace('&',' and ');
    });
      alert(JSON.stringify(testdata));
  });

answered Sep 24, 2014 at 6:33

user3627944

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2 Comments

GillesC Over a year ago

Works but the example replace & by and not the other way around like the original post so might be worth updating. It will also replace only the first instance of the searched string.

GillesC Over a year ago

Also worth mentioning this will loop over the array and that map is slower than a normal for.

Naeem Shaikh · Accepted Answer · 2014-09-24 06:44:13Z

1

Here is the fiddle http://jsfiddle.net/xj52nyj0/1/

You can convert the array to string using JSON.jsringify();

and then replace like this.

var arrayData = [
       "Safi Landmark Hotel and Suites",
       "Safi Landmark Hotel Suites",
       "Safi Landmark Hotel and Suites"
];
var x=JSON.stringify(arrayData);
x = x.split('S').join("N");

This doesnt use any looping.

answered Sep 24, 2014 at 6:44

Naeem Shaikh

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Comments

Cheery · Accepted Answer · 2014-09-24 06:50:57Z

0

No loop, no jQuery...

var arrayData = [
   "Safi Landmark Hotel and Suites",
   "Safi Landmark Hotel Suites",
   "Safi Landmark Hotel and Suites"
];

console.log(arrayData.join('|*|*|').replace(/and/g,'&').split('|*|*|'));

ps: '| * | * |' is just some unique delimeter..

edited Sep 24, 2014 at 6:50

answered Sep 24, 2014 at 6:35

Cheery

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