Warning: array_keys() expects parameter 1 to be array, null given

Question

Weird parser errors:

Notice: Undefined property: template::$param in 
    C:\xampp\htdocs\app\includes\classes\class.template.php on line 37

Warning: array_keys() expects parameter 1 to be array, null given in 
    C:\xampp\htdocs\app\includes\classes\class.template.php on line 37

Notice: Undefined property: template::$param in 
    C:\xampp\htdocs\app\includes\classes\class.template.php on line 37

Warning: array_values() expects parameter 1 to be array, null given in 
    C:\xampp\htdocs\app\includes\classes\class.template.php on line 37

Code:

public function newParam($trans, $value) {
    $this->param['{' . $trans . '}'] = $value;
}

public function getParam($content) {
    $content = str_replace(
        array_keys($this->param), 
        array_values($this->param), 
        $content
    );

    return $content;
}

Please note that this isn't any existing parser.

It appears that for some reason, your $this->param is null. — Hamatti
– Hamatti, Commented May 11, 2014 at 2:43
In addition to what you have here, we need to see the code where you are actually instantiating this class and calling getParam(). It would seem that $this->param is not initialized at the time getParam() is called. Is the $param property initialized as a class property, as in public $param = array();? — Michael Berkowski
– Michael Berkowski, Commented May 11, 2014 at 2:43
Please post the entire class declaration. I'm particularly interested in what $this->param contains. — Dave Chen
– Dave Chen, Commented May 11, 2014 at 2:43

Community · Accepted Answer · 2023-11-17 19:46:20Z

2

Init your "param":

function __construct() {
  $this->param = array();
}

You may also see the PHP Doc

Creating/modifying with square bracket syntax

An existing array can be modified by explicitly setting values in it.

This is done by assigning values to the array, specifying the key in brackets. The key can also be omitted, resulting in an empty pair of brackets ([]).

$arr[key] = value;
$arr[] = value;
// key may be an integer or string
// value may be any value of any type

edited Nov 17, 2023 at 19:46

CommunityBot

11 silver badge

answered May 11, 2014 at 2:49

user1293029

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Comments

Ranjith · Accepted Answer · 2019-07-25 14:01:24Z

1

Make sure fideloper/proxy version is 4.0 for laravel >= 5.5

"require": {
        "php": "^7.1.3",
        "**fideloper/proxy**": **"^4.0"**,

answered Jul 25, 2019 at 14:01

Ranjith

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