java split string with regular expression

Question

I have a string like "~~banana~apple~". I want to split that string with "~" is seperator and i want last element in the array after split is "" not "apple".

        String fruits = "~~banana~apple~";
        String[] arr = fruits.split("~");
        String last = "";  //Last string i need
        if (arr.length > 0 )
            last =  arr[arr.length-1];

        System.out.println("last: " + last);

//The result

last: apple

//but i want in this case the value of last must be "" because afer "apple" have "~".

Sorry my bad english.

The value is in fruits variable and you are splitting ten variable. Is that a typo or partial code. — Subir Kumar Sao
– Subir Kumar Sao, Commented Dec 7, 2013 at 16:10
There is nothing after your last ~ so there's nothing to point to as the last element. — Jeroen Vannevel
– Jeroen Vannevel, Commented Dec 7, 2013 at 16:11
@Jeroen Vannevel i want it must be an empty string because after apple have "~" — Nguyen Trung
– Nguyen Trung, Commented Dec 7, 2013 at 16:12
@Subir Kumar Sao Sorry i copy and forget to edit to English varriable (ten = Name in English) — Nguyen Trung
– Nguyen Trung, Commented Dec 7, 2013 at 16:15

Pshemo · Accepted Answer · 2016-03-28 14:08:48Z

3

I'm guessing that you are looking for split("~",-1). By default split removes empty strings ("") from the end, but with negative limit it will leave them.

edited Mar 28, 2016 at 14:08

answered Dec 7, 2013 at 16:12

Pshemo

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