Check if array is inside a string

Question

$comment = 'billie jean is not my lover she is just a girl';
$words = array('jean','lover','jean');
$lin = some_function_name($comment,$words);
($lin=3)

I tried substr_count(), but it doesn't work on array. Is there a builtin function to do this?

Is some_function_name supposed to return how many strings from $words were matched? — Nick Presta
– Nick Presta, Commented Nov 4, 2009 at 21:40
i think he wants to know if all items in the array are in the string provided? — Shadi Almosri
– Shadi Almosri, Commented Nov 4, 2009 at 22:10

Rick Pastoor · Accepted Answer · 2011-10-10 17:50:05Z

2

I would use array_filter(). This will work in PHP >= 5.3. For a lower version, you'll need to handle your callback differently.

$lin = sum(array_filter($words, function($word) use ($comment) {return strpos($comment, $word) !== false;}));

edited Oct 10, 2011 at 17:50

Rick Pastoor

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answered Nov 4, 2009 at 21:41

Jeremy DeGroot

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Comments

rogeriopvl · Accepted Answer · 2009-11-04 21:49:18Z

2

This is a simpler approach with more lines of code:

function is_array_in_string($comment, $words)
{
    $count = 0;
    foreach ($comment as $item)
    {
        if (strpos($words, $item) !== false)
            count++;
    }
    return $count;
}

array_map would probably produce a much cleaner code.

edited Nov 4, 2009 at 21:49

answered Nov 4, 2009 at 21:44

rogeriopvl

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Comments

manji · Accepted Answer · 2009-11-04 21:44:29Z

1

using array_intersect & explode:

to check all there:

count(array_intersect(explode(" ", $comment), $words)) == count($words)

count:

count(array_unique(array_intersect(explode(" ", $comment), $words)))

answered Nov 4, 2009 at 21:44

manji

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2 Comments

brianreavis Over a year ago

Wouldn't this unnecessarily guzzle memory? (exploding the entire comment string.)

manji Over a year ago

because we're searching for words, I thought of transforming the $comment to separate words (space delimited) before the search. Otherwise, with strpos & co functions, 'jean' will be found in 'billie jean' & 'billiejean'

brianreavis · Accepted Answer · 2009-11-04 21:49:53Z

0

I wouldn't be surprised if I get downvoted for using regex here, but here's a one-liner route:

$hasword = preg_match('/'.implode('|',array_map('preg_quote', $words)).'/', $comment);

answered Nov 4, 2009 at 21:49

brianreavis

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Comments

Felipe Ribeiro · Accepted Answer · 2009-11-04 22:08:03Z

0

You can do it using a closure (works just with PHP 5.3):

$comment = 'billie jean is not my lover she is just a girl';
$words = array('jean','lover','jean');
$lin = count(array_filter($words,function($word) use ($comment) {return strpos($comment,$word) !== false;}));

Or in a simpler way:

$comment = 'billie jean is not my lover she is just a girl';
$words = array('jean','lover','jean');
$lin = count(array_intersect($words,explode(" ",$comment)));

In the second way it will just return if there's a perfect match between the words, substrings won't be considered.

answered Nov 4, 2009 at 22:08

Felipe Ribeiro

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