Get an array of int from a String of numbers

Question

I have a long string of numbers,

String strNumbers = "123456789";

I need to get an int[] from this.

I use this method to get it:

public static int[] getIntArray(strNumbers)
{
    String[] strValues = strNumbers.split("");
    int[] iArr = new int[strValues.length];
    for(int i = 0; i < strValues.length; i++)
    {
        iArr[i] = Integer.parseInt(strValues[i]);
    }
    return iArr;
}

I get this error : java.lang.NumberFormatException: For input string: ""

My guess is that I cannot split a String that way. I tried all sorts of escape or Regex but nothing works.

Can anyone help?

thanks for the editing. I will get it right some day. ;)

jpl
– jpl

2013-04-10 14:14:44 +00:00
Commented Apr 10, 2013 at 14:14 — jpl
– jpl, Commented Apr 10, 2013 at 14:14

Subhrajyoti Majumder · Accepted Answer · 2013-04-10 14:03:40Z

9

Try

char[] chars = strNumbers.toCharArray();

and then iterate through the char array.

edited Apr 10, 2013 at 14:03

Subhrajyoti Majumder

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answered Apr 10, 2013 at 14:02

Zim-Zam O'Pootertoot

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1 Comment

jpl Over a year ago

This is a good idea, I feel a bit stupid because I did not think of that.

Bohemian · Accepted Answer · 2013-04-10 14:14:38Z

6

Your problem is the split regex. Try this instead:

String[] strValues = strNumbers.split("(?<=\\d)");

This splits after every digit (using a look behind regex), which will create an array of size zero for blank input.

edited Apr 10, 2013 at 14:14

answered Apr 10, 2013 at 14:07

Bohemian♦

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2 Comments

jpl Over a year ago

This is exactly what I was looking for. Thank you very much. I am kind of new to regex but I am getting there.

Bohemian Over a year ago

You're welcome :) I can recommend this site as a good regex reference site.

Buzz LIghtyear · Accepted Answer · 2013-04-10 14:03:36Z

1

You can use charAt() function to retrieve each character in the string and then do the parseInt()

answered Apr 10, 2013 at 14:03

Buzz LIghtyear

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Comments

Miquel · Accepted Answer · 2013-04-10 14:03:42Z

0

You could simply use a for loop going through your string and calling String.charAt(int)

answered Apr 10, 2013 at 14:03

Miquel

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Comments

Jean Logeart · Accepted Answer · 2013-04-10 14:05:31Z

0

Try:

char[] chars = strNumbers.toCharArray();
int[] iArr = new int[chars.length];
for(int i = 0 ; i < chars.length ; ++i) {
    iArr[i] = chars[i] - '0';
}

answered Apr 10, 2013 at 14:05

Jean Logeart

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Comments

user2264310 · Accepted Answer · 2013-04-10 14:05:37Z

0

You can use a loop statement to iterate the string. And then you use a substring method to chop the string into individual number. Using the substring() method you can define the length of the substring to be converted into number.

answered Apr 10, 2013 at 14:05

user2264310

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