def applejuice(q):
print THE FUNCTION NAME!
It should result in "applejuice" as a string.
7 Answers
This also works:
import sys
def applejuice(q):
func_name = sys._getframe().f_code.co_name
print func_name
Comments
def applejuice(**args):
print "Running the function 'applejuice'"
pass
or use:
myfunc.__name__
>>> print applejuice.__name__
'applejuice'
1 Comment
joel
this isn't from inside the function
import traceback
def applejuice(q):
stack = traceback.extract_stack()
(filename, line, procname, text) = stack[-1]
print procname
I assume this is used for debugging, so you might want to look into the other procedures offered by the traceback module. They'll let you print the entire call stack, exception traces, etc.
Comments
Another way
import inspect
def applejuice(q):
print inspect.getframeinfo(inspect.currentframe())[2]
Comments
You need to explain what your problem is. Because the answer to your question is:
print "applejuice"
2 Comments
wilhelmtell
maybe he means: def func(anothah_func): print anothah_func's name
Lennart Regebro
Well, that's definitely possible. We'll see if he says what the problem is.
This site gave me a decent explanation of how sys._getframe.f_code.co_name works that returns the function name.
http://code.activestate.com/recipes/66062-determining-current-function-name/
1 Comment
Stephane Rolland
Wlecome to SO! please, think about providing explanation, and not only pointing to external links.
def foo():
# a func can just make a call to itself and fetch the name
funcName = foo.__name__
# print it
print 'Internal: {0}'.format(funcName)
# return it
return funcName
# you can fetch the name externally
fooName = foo.__name__
print 'The name of {0} as fetched: {0}'.format(fooName)
# print what name foo returned in this example
whatIsTheName = foo()
print 'The name foo returned is: {0}'.format(whatIsTheName)
def applejuice(): print "thefunctionname"; orangejuice = applejuice; del applejuice; orangejuice();