Convert String to variable in PHP inside function argument

Question

below is the code I have created. My point here is to convert all strings inside the function argument.

For example, fname('variable1=value1&variable2=value2'); I need to convert variable1 & variable2 into ang variable as $variable1, $variable2 instead parsing a plain text. I found out eval() function is useful but it only takes one string which is the "variable1" and its value.

function addFunction($arg){
    echo eval('return $'. $arg . ';');
}
addFunction('variable1=value1&variable2=value2');

Now the problem is I got this error "Parse error: syntax error, unexpected '=' in D:\xampp\htdocs...\index.php(7) : eval()'d code on line 1". But if I have only one variable and value inside the function argument it works perfect, but I need to have more parameters here. Is this possible to do this thing or is there any other way to count the parameters before it can be evaluated?

Thank you,

Federkun · Accepted Answer · 2013-02-27 08:07:26Z

1

function addFunction($arg)
{
    parse_str($arg, $args);

    foreach ($args as $key => $val) {
        echo $key , " --> " , $val, "\n";
    }


}

addFunction('variable1=value1&variable2=value2');

Output

variable1 --> value1
variable2 --> value2

You can also use

function addFunction($arg)
{
    parse_str($arg);

    echo $variable2; // value2

}

addFunction('variable1=value1&variable2=value2');

edited Feb 27, 2013 at 8:07

answered Feb 26, 2013 at 16:47

Federkun

37.2k8 gold badges82 silver badges93 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

BenOfTheNorth · Accepted Answer · 2013-02-26 16:31:20Z

1

You are trying to create a variable with this name:

$variable1=value1&variable2=value2

You need to explode it at the & to get just the desired future variable names.

function addFunction($arg){

    echo eval('return $'. $arg . ';');
}

$string = 'variable1=value1&variable2=value2';

$array = explode('&', $string);

foreach($array as $part)
{
    addFunction($part);
}

answered Feb 26, 2013 at 16:31

BenOfTheNorth

2,8621 gold badge23 silver badges47 bronze badges

Comments

Ryan · Accepted Answer · 2013-02-26 16:32:10Z

1

You can break a string up using the PHP explode function, and then use eval to evaluate each variable indepedently.

 $myvars = explode ('$', 'variable1=value1&variable2=value2');

$myvars is then an array which you can parse and feed to eval as needed.

answered Feb 26, 2013 at 16:32

Ryan

28.4k10 gold badges58 silver badges83 bronze badges

Comments

Kristen Waite · Accepted Answer · 2013-02-26 16:33:02Z

1

Perhaps you can use explode()?

$varArr = explode("&",$arg);
foreach ($varArr as $varKey=>$varVal) {
    echo eval('return $'.$varKey.'='.$varVal.';');
}

answered Feb 26, 2013 at 16:33

Kristen Waite

1,4752 gold badges16 silver badges28 bronze badges

Comments

Husman · Accepted Answer · 2013-02-26 16:35:43Z

1

You need split the $arg at & to get each variable and then again at = to get each variable and value.

$arg = 'variable1=value1&variable2=value2';
$vars = explode('&', $arg);

foreach ($vars as $var) {
    $parts = explode("=", $var);
    echo eval('return $'. $parts[0] . '='. $parts[1] . ';');
}

answered Feb 26, 2013 at 16:35

Husman

6,93910 gold badges32 silver badges48 bronze badges

Comments

Hackerman · Accepted Answer · 2013-02-26 16:43:16Z

1

Something like this:

function addFunction($arg)
{
  $varArr = explode("&",$arg);
  $varResponse ="";

  foreach ($varArr as $varKey=>$varVal) {
   $varResponse = $varResponse."$".$varVal.";";
  }
   return $varResponse;
 }
  echo addFunction('variable1=value1&variable2=value2');

Saludos ;)

answered Feb 26, 2013 at 16:43

Hackerman

12.3k2 gold badges37 silver badges47 bronze badges

Collectives™ on Stack Overflow

Convert String to variable in PHP inside function argument

6 Answers 6

Comments

Comments

Comments

Comments

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

6 Answers 6

Comments

Comments

Comments

Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related