Unix timestamp to date from variable in PHP not working

Question

I have an array of Unix timestamps. I used the following code to make a file path of the timestamps array ($i is used later in a loop, but at first it gets value 0 and so it's correct):

$date = date('d-m-y', $timestamp[$i]);
$path = $dir . '/' . $date '.csv';

Let's say there many timestamps in the array. If i set $i = 0; $date is a string 06-01-13 (it returns the current day, though timestamp is many weeks old), and it ignores the timestamp. But if I replace $timestamp[$i] with 1257426933 the output string is correct (05-11-09).

What's wrong? My PHP version is PHP 5.3.10-1ubuntu3.4

Can you clarify what timestamp you are feeding and what date you are getting? — Pekka
– Pekka, Commented Jan 6, 2013 at 13:32

Adam Hopkinson · Accepted Answer · 2013-01-06 13:37:41Z

1

Most likely is that the $timestamp[$i] value is not what you expected?

var_dump($timestamp);

date() will give the current date if the second parameter is empty or not present.

edited Jan 6, 2013 at 13:37

Adam Hopkinson

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answered Jan 6, 2013 at 13:35

freakerd

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3 Comments

Laotse Over a year ago

Currently, array has following 6 values: var_dump($timestamp) array(6) { [0]=> int(1357426933) [1]=> int(1357430473) [2]=> int(1357434073) [3]=> int(1357437673) [4]=> int(1357441273) [5]=> int(1357498872) }

Laotse Over a year ago

Wait a minute, there is a mess in my timestamp function, I have a look at it

Laotse Over a year ago

Yes, of course. My fault. Timestamps were faulty as you can see. I give a wrong fromat to the function which makes them. So strtotime needs times in yyyy-mm-dd format... SOLVED

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