php to javascript int variable parsing

Question

I am trying to parse an int value from php into a javascript variable but it is not working.

The first alert correctly displays the int value, but the second says "undefined". How can you parse the php variable correctly into the variable "test" as an integer? I tried parseInt but it didn't work. The value is for a graph so I need to at some point use the fillRect() command, the alerts are for testing only. Thanks.

    alert('<?php echo( $graph_max_max_value ); ?>');
    var test = <?php $graph_max_max_value; ?>
    alert(test);

Try var test = <?php echo $graph_max_max_value; ?>

Wearybands
– Wearybands

2012-10-08 10:00:51 +00:00
Commented Oct 8, 2012 at 10:00 — Wearybands
– Wearybands, Commented Oct 8, 2012 at 10:00

Grant Thomas · Accepted Answer · 2012-10-08 10:01:14Z

3

var test = <?php echo $graph_max_max_value; ?>; should work.

This outputs using echo, which you forgot, and adds the statement terminating semi-colon at the end.

answered Oct 8, 2012 at 10:01

Grant Thomas

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4 Comments

Laurent Brieu Over a year ago

@user1334130, make sure this value is supposed to be an integer. If it's not, use this : var test = "<?php echo $graph_max_max_value; ?>";

user1334130 Over a year ago

Thanks Grant. Now it works perfectly. :) Will accept the answer as soon as I can.

user1334130 Over a year ago

@TWCrap yes but the answer from Thomas was more helpful.

Mathlight Over a year ago

@user1334130, it's your call, and if you find that, then you should do that ;-)

Quentin · Accepted Answer · 2012-10-08 10:00:20Z

2

You forgot to do anything to output the variable.

You want an echo, print, printf, etc.

(You also need to make sure that the data in PHP conforms to the syntax for a Number type in JavaScript.)

answered Oct 8, 2012 at 10:00

Quentin

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Comments

Wearybands · Accepted Answer · 2012-10-08 10:01:53Z

1

Try this

var test = <?php echo $graph_max_max_value; ?>,

and then

alert(test);

If you dont use echo then the value is undefined

answered Oct 8, 2012 at 10:01

Wearybands

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Comments

tsergium · Accepted Answer · 2012-10-08 10:07:49Z

0

You forgot an echo and you need to make sure you pass an integer value to your variable.

<script>
    <?php $graph_max_max_value = 1024;?>
    alert('<?php echo( $graph_max_max_value ); ?>');
    var test = '<?php echo $graph_max_max_value;?>';
    test.replace(/[^0-9]/g, '');
    alert(test);
</script>

answered Oct 8, 2012 at 10:07

tsergium

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