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Suppose I have a function that I want to plot for several values of a parameter all in the same window. For instance the function $f$ defined as 

f[a_,b_,c_,d_]:= a+Sin[b]*Exp[c]-d^4

If I now want to plot f[a,1,2,3] with respect to a from 0 to 1 I simply write 

Plot[f[a,1,2,3],{a,0,1}]

But suppose I want to instead plot f[a,b,2,3] same as before for a from 0 to 1 but now the parameter b takes on several values, say b = 0,1,2,3,4 and so on. How can I do this all in the same plot (preferably with different colors on each curve corr. to the various b-values)?

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  • $\begingroup$ You've seen Table[]? $\endgroup$ Commented Oct 12, 2015 at 14:23
  • $\begingroup$ I'll look it up. $\endgroup$ Commented Oct 12, 2015 at 14:24
  • $\begingroup$ @J.M.isback. OK I see what `Table[]' can do, but how can one implement it to write a smooth short code? Any tips? $\endgroup$ Commented Oct 12, 2015 at 14:26

1 Answer 1

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You can use Table for this:

Plot[Evaluate@Table[f[a, b, 2, 3], {b, 0, 5, 1}], {a, 0, 1}]

And you can also put there multiple parameters, so Table will use all of them.

enter image description here

You can use PlotLegend to specify the legend:

Plot[Evaluate@Table[f[a, b, 2, 3], {b, 0, 5, 1}], {a, 0, 1}, 
 PlotLegends -> LineLegend[Table[b, {b, 0, 5, 1}], LegendLabel -> x]]

enter image description here

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  • $\begingroup$ ooo sexy, I'll try it out and report back here. $\endgroup$ Commented Oct 12, 2015 at 14:27
  • $\begingroup$ Is there a simple way to add names to all the lines, e.g. some type of legend that explains? I mean I know I can write PlotLegends -> {"1","2",...} and so on, but a more automatic code would be nice. Sorry to bother you so much. $\endgroup$ Commented Oct 12, 2015 at 14:32
  • $\begingroup$ @ShutupandCalculate look up PlotLegends. $\endgroup$ Commented Oct 12, 2015 at 14:34
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    $\begingroup$ Try adding PlotTheme -> "Detailed" as an option for Plot for good looking plots with automatic labels. $\endgroup$ Commented Oct 12, 2015 at 14:38
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    $\begingroup$ Man this answer is just all that. Thanks a lot everyone! $\endgroup$ Commented Oct 12, 2015 at 15:14

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