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A 0-1 linear programming problem with three variables can have at most $3! = 6$ acceptable solutions? Is this right or wrong?

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At most 8 solutions. Two values per variable. By rule of independence, we multiply $2^{3} = 8$.

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  • $\begingroup$ Thanks didn't find that in my notes. $\endgroup$ Commented Aug 9, 2015 at 15:02
  • $\begingroup$ Don't rely on notes. Rely on basic principles. How did you come up with $3!$ to begin with? $\endgroup$ Commented Aug 9, 2015 at 22:18

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