Is there a better way to do this using chaining?
var url = "www.mycompany.com/sites/demo/t1"
var x = url.split('/');
console.log(x);
var y = x.pop();
console.log(y,x);
var z = x.join("/");
console.log(z);I tried something like but wouldn't work since pop just returns the last value and not the rest:
parentUrl = self.attr('Url').split("/").pop().join("/");
pop() mutates the underlying list: it removes the last item (and returns it).
It seems you're looking for slice:
"www.mycompany.com/sites/demo/t1".split('/').slice(0, -1).join('/')
// -> gives: "www.mycompany.com/sites/demo"
.slice(0, -1) gives the elements of the list from the start until the end minus one item.
However, this is a very poor solution to drop the last path element from a URL. In particular, splitting a string to an array, drop the last element and join the string again is inefficient. It would be better to use lastIndexOf to find the position of the last /, and then substr to extract the part of the string before the last /.
var s = "www.mycompany.com/sites/demo/t1";
s.substr(0, s.lastIndexOf('/'));
