1

I made a small little IoT device to control my light chains from my phone, I'm using a MOSFET to turn the power on or off, using an esp32 connected to the MOSFET, both esp32 and light chain is supplied from a standard 6v phone charger I just clipped the wires and used it,

I have a voltage regulator on the esp32 as seen on the image, when I run the system the esp32 slowly heats up to around 40-50 Celcius, and I can hear a small whinny sound from the chip, the esp32 is getting 3.3v as I should when I measure with a multimeter

what's wrong?

(btw it works with turning lights on and off, not sure if those was the resisters i used)

enter image description here enter image description here

Improve this question
9
  • Is that a map of where the nearest starbucks is? If it's supposed to be a schematic it's completely meaningless and impossible to read. Commented Oct 2, 2020 at 10:46
  • lol, ye sorry I didn't really know any good side to make the schematic on, didn't think it was that important, just wanted to give a general idea of what the circuit was Commented Oct 2, 2020 at 10:56
  • 1
    The question editor also has the function to draw schematics in it. Just click at the "Schematics" button (the one with the little schematic diagram) in the question editor and then you can create a proper schematic, which will directly tie into your question. Commented Oct 2, 2020 at 11:00
  • There's a schematic editor available right from the editor with Ctrl-M. Commented Oct 2, 2020 at 11:05
  • 1
    What is connected to what? Are you running your light chain from the output of your voltage regulator? What is the output voltage of the regulator? How are you powering the ESP32? If the voltage regulator is putting out 5V and you're using that to power your light chain and as VIN to your ESP32, the ESP's voltage regulator is still having to drop 5V down to 3.3. That shouldn't generate a lot of heat unless you are drawing significant current from the ESP's regulator. Commented Oct 2, 2020 at 12:41

0

Reset to default

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.