sed Extract version number from string (only version, without other numbers)

Question

I want to achieve the same as explained in sed: Extract version number from string, but taking into consideration only the first sequence of numbers or even safer, tell sed to keep only the sequence of numbers following the name of the command, leaving out the rest.

I have: Chromium 12.0.742.112 Ubuntu 11.04

I want: 12.0.742.112

Instead of: 12.0.742.11211.04

I now know that using head or tail with sort it is possible to display the largest/smallest number, but how can I tell sed to consider the first sequence only?

EDIT: I forgot to mention that I'm using bash.

Beta · Accepted Answer · 2011-09-23 00:06:39Z

18

The first number? How about:

sed 's/[^0-9.]*\([0-9.]*\).*/\1/'

answered Sep 23, 2011 at 0:06

Beta

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3 Comments

ssi-anik Over a year ago

If someone reaches here looking for extracting 1.1.1 from v1.1.1, then you can use sed 's/v\(.*\)/\1/' github.com/ssi-anik/medium-unlimited/blob/…

Beta Over a year ago

@ssi-anik: or s/.//

ssi-anik Over a year ago

Makes sense, didn't think about it tho. :D

Kusalananda · Accepted Answer · 2011-09-23 07:24:58Z

4

Here's a solution that doesn't rely on the position of the command in your string, but that will pick up whatever comes after it:

command="Chromium"

string1="Chromium 12.0.742.112 Ubuntu 11.04"
string2="Ubuntu 11.04 Chromium 12.0.742.112"

echo ${string1} | sed "s/.*${command} \([^ ]*\).*$/\1/"
echo ${string2} | sed "s/.*${command} \([^ ]*\).*$/\1/"

answered Sep 23, 2011 at 7:24

Kusalananda

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Comments

Kusalananda · Accepted Answer · 2011-09-22 14:33:28Z

1

With cut (assuming you always want the second bit of info on the line):

$ echo "Chromium 12.0.742.112 Ubuntu 11.04" | cut -d' ' -f2
12.0.742.112

answered Sep 22, 2011 at 14:33

Kusalananda

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5 Comments

octosquidopus Over a year ago

Well no, sometimes the version precedes the name

Kusalananda Over a year ago

@octosquidopus, so, how do we know which version you want?

octosquidopus Over a year ago

I want the number following the name of the command, or if not present, the first number displayed.

Kusalananda Over a year ago

@octosquidopus How do we know what the name of the command is?

octosquidopus Over a year ago

Since it's in a script, it can be previously stored in a variable. But anyway, it doesn't really matter what's the name of the command, as long as non-numbers preceding the version are removed.

bash-o-logist · Accepted Answer · 2011-09-23 01:05:05Z

1

well, if you are using bash, and if what you want is always on 2nd field,

$ string="Chromium 12.0.742.112 Ubuntu 11.04"
$ set -- $string; echo $2
12.0.742.112

answered Sep 23, 2011 at 1:05

bash-o-logist

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Dov Grobgeld · Accepted Answer · 2011-09-22 14:36:19Z

0

The following perl command does it:

echo "Chromium 12.0.742.112 Ubuntu 11.04" | perl -ne '/[\d\.]+/ && print $&'

answered Sep 22, 2011 at 14:36

Dov Grobgeld

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Magnus · Accepted Answer · 2021-10-31 14:32:14Z

0

This will match/output the first occurance of number(s) and dot(s):

sed -rn "s/([^0-9]*)([0-9\.]+)([^0-9]*.*)/\2/ p"

I've thrown a couple of narly strings at it and it held water :)

answered Oct 31, 2021 at 14:32

Magnus

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